Sql Postgres检查数组值是否在列表中

如何检查单行中的任何数组值是否在我的列表中？ 这是我的桌子。我们叫它ABC吧

        id        |   page_id   |                                  values                                   
------------------+-------------+-------------------------------------------------------------------------
 1376092679147519 |     xyz     | {6004036173148,6003373173651,6003050657850}
 1375487155874738 |     xyz     | {6003301698460,6003232518610}
 1497527026945449 |     xyz     | {6003654559478,6003197656807}
 1375388575884596 |     xyz     | {6003512053894,6003450241842,6003051414416}
 1319144441504401 |     xyz     | {6004001256506,6003514818642,6003400993421}

我的目标是选择那些行，其中一个值出现在给定列表“6004036173148”、“6003197656807”中

SELECT id, page_id, values from ABC WHERE -SOME CLAUSE- IN ('6004036173148', '6003197656807');

        id        |   page_id   |                                  values                                   
------------------+-------------+-------------------------------------------------------------------------
 1376092679147519 |     xyz     | {6004036173148,6003373173651,6003050657850}
 1497527026945449 |     xyz     | {6003654559478,6003197656807}

下面是我的PosgreSQL表的结构

                             Table "public.ABC"
       Column       |           Type           |       Modifiers        
--------------------+--------------------------+------------------------
 id                 | character varying        | not null
 page_id            | character varying        | not null
 values             | character varying[]      | 
Indexes:
    "ABC_pkey" PRIMARY KEY, btree (id)

---

如果我正确理解，您需要：

select * from t
where "values" && '{6004036173148,6003197656807}'::character varying[]

编辑

如果需要提取某些值，则可以使用unnest函数

请注意，若同一数组包含搜索列表中的多个值，则该行将重复。看看这个id=2的示例输出，您可以看到，关于我所说的内容：

with t(id, values) as(
    select 1, '{6004036173147,6003373173651,6003050657840}'::character varying[]
    union all
    select 2, '{6004036173148,6003373173652,6003050657850}'::character varying[]
    union all
    select 3, '{6004036173149,6003373173653,6003050657860}'::character varying[]
)


select tt.* from  
(select t.*, unnest(values) unn from t) tt
inner join (select unnest('{6003373173651,6004036173148,6003373173652}'::character varying[]) v  ) lst
on tt.unn = lst.v

---

只是出于好奇，您会如何在tsql中做到这一点？SQL Server有数组类型吗？我不这么认为。如果是这样，我们将如何在tsql中使用数组？或者我错过了你的问题？我想你可以假装：创建表temp id VARCHAR20，page_id VARCHAR10，rValues VARCHAR100插入临时值'1376092679147519'，'xyz'，'600403617314860033731736516003050657850}'，'1375487155874738'，'xyz'，'600330694603232518610}'，'1497026945449'，'xyz'，'{60036545594786003197656807}、'1375388575884596'、'xyz'、'600351205389460034502418426003051414416}、'1319144441504401'、'xyz'、'60040012565066035148186426003400993421}从临时索引“%6003514818642%”中选择*，右值>0侧注：尽量不要将保留字如值用作列名