如何在sql server中在一行上添加柱基？

我有这张桌子

Row Title   Code    RegDate     Amount
----------------------------------------------------------
1   typea   203170  1396/12/29  150760000000    --Eur
1   typea   203251  1396/12/29  169928736       --Usd
2   typeb   201310  1396/12/29  32794373868351
3   typec   201441  1396/12/29  899750000
6   typed   201216  1396/12/29  23411268063599
8   typee   201181  1396/12/29  86687000        --Eur
8   typee   201211  1396/12/29  81483719480611  --Usd
9   typef   201212  1396/12/29  52595043810
10  typeh   201213  1396/12/29  3630924097

如何将第1行和第8行合并为一行，就像这样的结果

Row Title   Code    RegDate     Amount          Amount_Usd
----------------------------------------------------------
1   typea   203170  1396/12/29  150760000000    169928736
2   typeb   201310  1396/12/29  32794373868351  0
3   typec   201441  1396/12/29  899750000       0
6   typed   201216  1396/12/29  23411268063599  0
8   typee   201181  1396/12/29  86687000        81483719480611
9   typef   201212  1396/12/29  52595043810     0
10  typeh   201213  1396/12/29  3630924097      0

违约金额为欧元 谢谢你试试这个-

SELECT A.Row,A.Title,B.Code,A.RegDate,A.Amount,A.Amount_Usd FROM
(
    SELECT Row,Title,RegDate,
    ISNULL(SUM(CASE WHEN Code NOT IN (203251 ,201211) THEN Amount ELSE NULL END),0) Amount,
    ISNULL(SUM(CASE WHEN Code IN (203251 ,201211) THEN Amount ELSE NULL END),0)Amount_Usd
    FROM your_table
    GROUP BY Row,Title,RegDate
)A
INNER JOIN your_table B
ON A.Row = B.Row  and B.Code NOT IN (203251 ,201211)

---

您只需要在此处进行一些条件聚合：

--Sample Data
WITH VTE AS(
    SELECT *
    FROM (VALUES(1   ,'typea',203170,'1396/12/29',150760000000),
                (1   ,'typea',203251,'1396/12/29',169928736),   
                (2   ,'typeb',201310,'1396/12/29',32794373868351),
                (3   ,'typec',201441,'1396/12/29',899750000),
                (6   ,'typed',201216,'1396/12/29',23411268063599),
                (8   ,'typee',201181,'1396/12/29',86687000),
                (8   ,'typee',201211,'1396/12/29',81483719480611),
                (9   ,'typef',201212,'1396/12/29',52595043810),
                (10  ,'typeh',201213,'1396/12/29',3630924097)) V([Row],Title,Code, RegDate, Amount))
--Solution
SELECT Row,
       Title,
       MIN(CASE WHEN Code NOT IN (203251,201211) THEN Code END) AS Code,
       RegDate,
       ISNULL(SUM(CASE WHEN Code NOT IN (203251,201211) THEN Amount END),0) AS Amount,
       ISNULL(SUM(CASE WHEN Code IN (203251,201211) THEN Amount END),0) AS Amount_Usd
FROM VTE
GROUP BY [Row],[Title],RegDate;

---

不需要CTE，我的咖啡还没开始喝。

你怎么知道哪个金额是欧元，哪个是美元？代码是203251，201211是美元，所有代码都是欧元81483719480611是巨大的金额。你的公司让初学者做编程？这是样本你试过了吗？它不符合OP的要求。数据库更新。在组中添加代码时出现了一些问题。你应该修正这个解释。它与查询不匹配。谢谢@GordonLinoff。我修改了SQL，但没有修改解释。