SQL查询添加计数信息

我有一个很好的查询：

SELECT
 b.BG_BUG_ID as Defect
FROM
 BUG b
JOIN LINK l ON b.BG_BUG_ID = l.LN_BUG_ID
JOIN TEST t ON l.LN_ENTITY_ID = t.TS_TEST_ID
WHERE
 (b.BG_STATUS = 'Open') OR
 (b.BG_STATUS LIKE '%Re%') OR
 (b.BG_STATUS LIKE '%En%') OR
 (b.BG_STATUS = 'Fixed') OR
 (b.BG_STATUS = 'New') AND
 (l.LN_ENTITY_TYPE = 'TEST')
ORDER BY b.BG_BUG_ID ASC

输出为：

DEFECT
------
2222
3333
4444

现在，我想为每个b.BG\u BUG\u ID添加一行t.TS\u TEST\u ID的总数作为缺陷，因此它应该如下所示：

DEFECT Number_of_test_ids
------ ------------------
2222    26
3333    14
4444    55

我不知道在哪里添加选择计数（？）以生成结果

SELECT
 b.BG_BUG_ID as Defect, count(distinct t.TS_TEST_ID) as Number_of_test_IDs
FROM
 BUG b
JOIN LINK l ON b.BG_BUG_ID = l.LN_BUG_ID
JOIN TEST t ON l.LN_ENTITY_ID = t.TS_TEST_ID
WHERE
 (b.BG_STATUS = 'Open') OR
 (b.BG_STATUS LIKE '%Re%') OR
 (b.BG_STATUS LIKE '%En%') OR
 (b.BG_STATUS = 'Fixed') OR
 (b.BG_STATUS = 'New') AND
 (l.LN_ENTITY_TYPE = 'TEST')
GROUP BY B.BG_BUG_ID
ORDER BY b.BG_BUG_ID ASC

您正在使用需要GROUPBY子句的聚合函数

---

如果要计算重复的t.ts_测试_ID，可能需要删除distinct；或者，如果您知道不存在重复项，或者您确实想将同一id计数两次。

b.BG\u BUG\u id作为缺陷，计数（*）…

，然后在下订单之前：add

GROUP by b.BG\u BUG\u id

，在这种情况下，重复项不存在。我错过了小组赛！多亏了你，我的头痛会好起来的：）