按计数和排名分组的TSQL

假设我有以下几点：

DECLARE @Name TABLE (Name VARCHAR(MAX));

INSERT INTO @Name VALUES ('bob'),('bob'),('john'),('john'),('mark'),('mark'),('mark'),('lisa');

SELECT  Name,
COUNT(Name) AS TOTALS
FROM @Name
GROUP BY Name
ORDER BY TOTALS DESC;

---

如何使用Rank（）或densite_Rank（）根据计数获得排名？

如果需要排名列，可以将其与

分组依据一起使用：

SELECT n.Name, COUNT(*) as TOTALS,
       RANK() OVER (ORDER BY COUNT(*) DESC) as Total_Rank
FROM @Name n
GROUP BY n.Name
ORDER BY TOTALS DESC;

如果您想要排名列，可以将其与
分组依据一起使用
：

SELECT n.Name, COUNT(*) as TOTALS,
       RANK() OVER (ORDER BY COUNT(*) DESC) as Total_Rank
FROM @Name n
GROUP BY n.Name
ORDER BY TOTALS DESC;

试试这个：

SELECT *
    , RANK() OVER(ORDER BY totals DESC) AS Rank 
FROM
(
    SELECT  Name,
    COUNT(Name) AS TOTALS
    FROM @Name
    GROUP BY Name
) a

试试这个：

SELECT *
    , RANK() OVER(ORDER BY totals DESC) AS Rank 
FROM
(
    SELECT  Name,
    COUNT(Name) AS TOTALS
    FROM @Name
    GROUP BY Name
) a

但是既然马克有3个，是他们中最多的，我怎么把他列为1呢？@ACsteel只是颠倒顺序--
orderbycount（*）DESC
但是既然马克有3个，是他们中最多的，我怎么把他列为1呢？@ACsteel只是颠倒顺序--
orderbycount（*）DESC