Sql 如何使用ORACLE数据库根据特定文本对列进行分组和求和

我是甲骨文的新手。尝试根据特定文本对列进行分组并对其他列求和

假设我有下面的表格

我想把所有姓的人都分组。如下

我不知道该怎么做。 注意：可能有多个名称，但我只想筛选Sharma、Decosta和Liver

更新问题。 很抱歉更新了这个问题。但在真实场景中，搜索字符串并不总是最后一个

我再举一个例子。

输出

您可以使用regexp\u substr：

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到目前为止提供的查询似乎确实能够满足您的需求。但以下情况确实如此：

With inputs as
(
    select 'Rahul Kumar Sharma' as Name, 10 as No_of_beer_bottles from dual union all
    select 'Rohith Kumar Sharma' as Name, 5 as No_of_beer_bottles from dual union all
    select 'Sharma' as Name, 20 as No_of_beer_bottles from dual union all
    select 'Rahul Kumar Varma' as Name, 10 as No_of_beer_bottles from dual
)
select  SUBSTR(name,Instr(name,' ',-1)+1) as Name, sum(No_of_beer_bottles) as No_of_beer_bottles
from    inputs
group by SUBSTR(name,Instr(name,' ',-1)+1);

输出：

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如果您使用一个包含所有要搜索的单词的表，或者像我下面所做的那样在一个公共表表达式中定义它们，那么您可以在该搜索词上进行连接，然后对数值列求和

问题1 结果1 问题2 结果2

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应该是总和。对吧？我得到下面的结果不是求和。姓氏计数Decosta 1 Decosta 1 Sharma 2 Liver 1 Sharma 1正确，应为总和。我试着从select regexp_substrname中选择last_name，sumcount，“[^]+$”作为last_name，count*作为啤酒组的计数，按regexp_substrname，[^]+$”按last_name分组；但是力help@Varun，您是否尝试了我发布的解决方案？工作正常吗？@Ranagal。是的，应该是sum，现在是。你如何确定姓是什么？如果这是一场比赛呢？最好将Name列拆分为两列，即First_Name和Last_Name。不幸的是，这不是真实的数据。我有一个字符串，我需要找到一些关键字的基础上。所以我不能分开它狗走了狗算一次还是两次？狗不能使用笔算是狗和笔的一次出现吗？肖恩·潘（Sean Penn）在宾夕法尼亚州旅行，直到到达倒数第二英里时没有受到处罚。那里有多少支笔？嘿，感谢ans。这对给定的问题有效。但不幸的是，在真实场景中，姓氏最终不会出现。基本上我创建了虚拟日期。简言之，我有一个字符串，我需要基于该字符串搜索列，并对其值求和。搜索字符串已给定。@Rangal已更新question@Varun好啊你如何知道你必须提取什么并将其命名？如果你有规则。告诉我们，我们将尝试。这是一个预定义的单词，在上面的例子中是pen和dog

With inputs as
(
    select 'Rahul Kumar Sharma' as Name, 10 as No_of_beer_bottles from dual union all
    select 'Rohith Kumar Sharma' as Name, 5 as No_of_beer_bottles from dual union all
    select 'Sharma' as Name, 20 as No_of_beer_bottles from dual union all
    select 'Rahul Kumar Varma' as Name, 10 as No_of_beer_bottles from dual
)
select  SUBSTR(name,Instr(name,' ',-1)+1) as Name, sum(No_of_beer_bottles) as No_of_beer_bottles
from    inputs
group by SUBSTR(name,Instr(name,' ',-1)+1);

WITH
    search_words (word)
    AS
        (SELECT 'Sharma' FROM DUAL
         UNION ALL
         SELECT 'Decosta' FROM DUAL
         UNION ALL
         SELECT 'Liver' FROM DUAL),
    d (name, num_beers)
    AS
        (SELECT 'Ravi Sharma', 1 FROM DUAL
         UNION ALL
         SELECT 'Sam Decosta', 4 FROM DUAL
         UNION ALL
         SELECT 'Jhony Liver', 5 FROM DUAL
         UNION ALL
         SELECT 'Ravi Sharma', 2 FROM DUAL
         UNION ALL
         SELECT 'Rohul Sharma', 3 FROM DUAL
         UNION ALL
         SELECT 'Jhon Decosta', 3 FROM DUAL
         UNION ALL
         SELECT 'V Decosta', 3 FROM DUAL)
  SELECT sw.word, SUM (d.num_beers) AS total_beer
    FROM search_words sw, d
   WHERE INSTR (UPPER (d.name), UPPER (sw.word)) > 0
GROUP BY sw.word;

      WORD    TOTAL_BEER
__________ _____________
Decosta               10
Sharma                 6
Liver                  5

WITH
    search_words (word)
    AS
        (SELECT 'Pen' FROM DUAL
         UNION ALL
         SELECT 'Dog' FROM DUAL),
    d (name, quantity)
    AS
        (SELECT 'Ravi have red pens', 2 FROM DUAL
         UNION ALL
         SELECT 'Sam''s grifriend have black dogs', 4 FROM DUAL
         UNION ALL
         SELECT 'Jhony has blue pen', 1 FROM DUAL
         UNION ALL
         SELECT 'Ravi has white dog', 1 FROM DUAL
         UNION ALL
         SELECT 'Rahul has small dogs', 3 FROM DUAL
         UNION ALL
         SELECT 'There are pens inside Jhon''s car', 3 FROM DUAL
         UNION ALL
         SELECT 'My dog and me are flying.', 1 FROM DUAL)
  SELECT sw.word, SUM (d.quantity) AS total_quantity
    FROM search_words sw, d
   WHERE INSTR (UPPER (d.name), UPPER (sw.word)) > 0
GROUP BY sw.word;

   WORD    TOTAL_QUANTITY
_______ _________________
Dog                     9
Pen                     6