Sql 使用多个分层级别按值排序行
我有一个分级产品价格列表,它们的价格已经汇总。分层级别为集群、商店和货架 我想对这些产品的价格进行分级。每个级别都需要排序。以下是预期结果的示例: 现在,我可以在货架级别对价格进行排序,但还不能在商店或集群级别进行排序:Sql 使用多个分层级别按值排序行,sql,oracle,sorting,hierarchy,Sql,Oracle,Sorting,Hierarchy,我有一个分级产品价格列表,它们的价格已经汇总。分层级别为集群、商店和货架 我想对这些产品的价格进行分级。每个级别都需要排序。以下是预期结果的示例: 现在,我可以在货架级别对价格进行排序,但还不能在商店或集群级别进行排序: SELECT cluster_id, store_id, shelf_id, price FROM ( SELECT * FROM ( SELECT p.*, ROW_NUMBER () OVER (
SELECT cluster_id, store_id, shelf_id, price FROM (
SELECT * FROM (
SELECT p.*,
ROW_NUMBER () OVER (
ORDER BY
cluster_id ASC NULLS FIRST,
store_id ASC NULLS FIRST,
price DESC
) AS rn
FROM (SELECT * FROM products) p
)
)
ORDER BY rn;
我的实际结果是:
我使用的是Oracle数据库12c
样本数据
CREATE TABLE products (
cluster_id VARCHAR2(30),
store_id VARCHAR2(30),
shelf_id VARCHAR2(40),
price NUMBER(*,2)
);
INSERT INTO products VALUES ('10','230',NULL,120);
INSERT INTO products VALUES (NULL,NULL,NULL,500);
INSERT INTO products VALUES ('10','230','967',40);
INSERT INTO products VALUES ('10',NULL,NULL,300);
INSERT INTO products VALUES ('50','430','863',50);
INSERT INTO products VALUES ('50','170',NULL,70);
INSERT INTO products VALUES ('10','500','783',100);
INSERT INTO products VALUES ('50','170','798',20);
INSERT INTO products VALUES ('50','480',NULL,80);
INSERT INTO products VALUES ('50','430',NULL,50);
INSERT INTO products VALUES ('10','500',NULL,180);
INSERT INTO products VALUES ('50','480','486',60);
INSERT INTO products VALUES ('10','230','296',80);
INSERT INTO products VALUES ('50',NULL,NULL,200);
INSERT INTO products VALUES ('10','500','344',80);
INSERT INTO products VALUES ('50','480','234',20);
INSERT INTO products VALUES ('50','170','368',50);
我想这会管用的
with t as (
select cluster_id
, store_id
, shelf_id
, price
, row_number() over (partition by cluster_id order by price desc) cluster_sort
, row_number() over (partition by cluster_id, store_id order by price desc) store_sort
, row_number() over (partition by cluster_id, store_id, shelf_id order by price desc) shelf_sort
)
select cluster_id
, store_id
, shelf_id
, price
from t
order by cluster_sort
, store_sort
, shelf_sort
;
我想这会管用的
with t as (
select cluster_id
, store_id
, shelf_id
, price
, row_number() over (partition by cluster_id order by price desc) cluster_sort
, row_number() over (partition by cluster_id, store_id order by price desc) store_sort
, row_number() over (partition by cluster_id, store_id, shelf_id order by price desc) shelf_sort
)
select cluster_id
, store_id
, shelf_id
, price
from t
order by cluster_sort
, store_sort
, shelf_sort
;
此排序方法可提供所需的输出:
select p.*
from products p
order by
sum(case when store_id is not null and shelf_id is not null then price end)
over (partition by cluster_id) desc,
sum(case when store_id is not null and shelf_id is not null then price end)
over (partition by cluster_id, store_id) desc,
case when shelf_id is null then 1 end, price desc
此排序方法可提供所需的输出:
select p.*
from products p
order by
sum(case when store_id is not null and shelf_id is not null then price end)
over (partition by cluster_id) desc,
sum(case when store_id is not null and shelf_id is not null then price end)
over (partition by cluster_id, store_id) desc,
case when shelf_id is null then 1 end, price desc
您的查询不起作用,它按价格对所有集群进行排序,然后按价格对所有夫妇集群/商店等进行排序。您的查询不起作用,它按价格对所有集群进行排序,然后按价格对所有夫妇集群/商店等进行排序。。。