用于从不同表中获取信息的SQL查询

需要有关sql查询的帮助。 我有两张桌子

火柴

    first_referee_arbitr_id
    second_referee_arbitr_id
    home_team
    guest_team
    date

仲裁人

    id
    name
    surname

第一仲裁人仲裁人id

和

第二仲裁人仲裁人id

来自仲裁人表（id）

因此，我需要计算每名裁判参加比赛的次数：

   referee_first_count | referee_second_count | Arbitr Surname | Arbitr Name 

我现在的问题是：

SELECT  T1.referee_first_count, T2.referee_second_count, T1.surname, T1.name
FROM (
    select matches.first_referee_arbitr_id, q.surname, q.name, count(*) AS referee_first_count
    FROM matches
    JOIN (
      SELECT name, surname, id
      FROM arbitrs
    ) as q ON matches.first_referee_arbitr_id=q.id
    GROUP BY matches.first_referee_arbitr_id, q.name, q.surname
    ORDER BY referee_first_count DESC
  ) T1 FULL OUTER JOIN
  (
    select matches.second_referee_arbitr_id, arbitr.surname, arbitr.name, count(*) AS referee_second_count
    FROM matches
    JOIN (
      SELECT name, surname, id
      FROM arbitrs
    ) as arbitr ON matches.second_referee_arbitr_id=arbitr.id
    GROUP BY matches.second_referee_arbitr_id, arbitr.name, arbitr.surname
    ORDER BY referee_second_count DESC
  ) T2
  ON (
  (T1.name = T2.name) AND (T1.surname = T2.surname)
  )

示例

仲裁人：

 id | Name | Surname
  1   John    Rambler
  2   Steve   Crystler
  3    Tom    Ferguson

匹配项：

 first_referee_arbitr_id| second_referee_arbitr_id| home_team | guest_team | date
         1                                            Chelsea     Everton     22.06.2020 
         2                          1                 Liverpool   Lester      28.06.2020 
         3                                            Dinamo K    Dinamo M    06.07.2020
         1                          2                 Juventus    Dinamo K    10.10.2020
         3                                            Dinamo K    Chelsea     20.20.2020

结果:

   referee_first_count | referee_second_count | surname | name
        2                       1                Rambler   John
        1                       1                Crystler  Steve
        2                       0                Ferguson  Tom
                                                 

我现在使用上面的查询得到的结果：

   referee_first_count | referee_second_count | surname | name
        2                       1                Rambler   John
        1                       1                Crystler  Steve
        2                       NULL                NULL      NULL

---

首先聚合

匹配项

表（两次），然后将其左键连接到

仲裁人

表：

SELECT a.name , a.Surname , ISNULL(fir.first_count,0) , ISNULL( sec.sec_count,0)
FROM Arbitrs a
LEFT JOIN (
        SELECT first_referee_arbitr_id,COUNT(*) as first_count
        FROM Matches
        GROUP BY first_referee_arbitr_id
        ) fir
        ON fir.first_referee_arbitr_id = a.id 
LEFT JOIN (
        SELECT second_referee_arbitr_id,COUNT(*) as sec_count
        FROM Matches
        GROUP BY second_referee_arbitr_id
        ) sec
        ON sec.second_referee_arbitr_id = a.id 

---

这就是你得到的结果吗？否则你的查询结果是什么？@asi我需要得到这个结果，现在我用这个得到另一个结果query@asi我现在添加了我的结果，这对我很有帮助。谢谢，我忘了提一下，最好得到每行的总和，然后将结果添加到总计列中

SELECT a.name , a.Surname , ISNULL(fir.first_count,0) , ISNULL( sec.sec_count,0)
FROM Arbitrs a
LEFT JOIN (
        SELECT first_referee_arbitr_id,COUNT(*) as first_count
        FROM Matches
        GROUP BY first_referee_arbitr_id
        ) fir
        ON fir.first_referee_arbitr_id = a.id 
LEFT JOIN (
        SELECT second_referee_arbitr_id,COUNT(*) as sec_count
        FROM Matches
        GROUP BY second_referee_arbitr_id
        ) sec
        ON sec.second_referee_arbitr_id = a.id