Ssas 每个事务的MDX开始和结束时间_Ssas_Mdx_Cubes

Ssas 每个事务的MDX开始和结束时间

ssas mdx

Ssas 每个事务的MDX开始和结束时间,ssas,mdx,cubes,Ssas,Mdx,Cubes,我希望你能帮助我，我已经尝试了很多方法，但都没有成功。我正在尝试获取玩家帐号、日期、开始和结束日期时间，并可能计算开始和结束时间之间的游戏持续时间我希望输出像这样玩家帐号|游戏日期|开始时间|结束时间|游戏持续时间|实际时间我似乎总是返回一整天的开始和结束时间，而不是每个帐户 WITH SET [MySet] AS [Customer].[Player Account Number].Children* Head ( NonEm

我希望你能帮助我，我已经尝试了很多方法，但都没有成功。我正在尝试获取玩家帐号、日期、开始和结束日期时间，并可能计算开始和结束时间之间的游戏持续时间

我希望输出像这样

我似乎总是返回一整天的开始和结束时间，而不是每个帐户

 WITH 
  SET [MySet] AS 
      [Customer].[Player Account Number].Children*
      Head
      (
        NonEmpty
        (
          [Start Time].[Hour].Children
         ,[Measures].[Actual Win]
        )
       ,1
      )*
      Tail
      (
        NonEmpty
        (
          [End Time].[Hour].Children
         ,[Measures].[Actual Win]
        )
       ,1
      ) 
SELECT 
  {[Measures].[Actual Win]} ON 0
 ,{[MySet]} ON 1
FROM 
(
  SELECT 
      [Customer].[Player Account Number].&[1040002184]
    : 
      [Customer].[Player Account Number].&[1040002198] ON 0
  FROM Ratings
)
WHERE 
  {[Gaming Date].[Full Date].&[20150101]};

您有一个静态集（总是返回相同的成员）。使用

EXISTING

关键字计算当前上下文中的开始和结束时间

with member [Measures].[StartDate] as

    EXISTING    
    HEAD(
            nonempty(
                    [Start Time].[Hour].Children,[Measures].[Actual Win]
                    ) ,1
        ).ITEM(0).ITEM(0).MEMBERVALUE



member [Measures].[EndDate] as
    EXISTING
    TAIL(
            nonempty(
                    [End Time].[Hour].children,[Measures].[Actual Win]
                    ) ,1            
        ).ITEM(0).ITEM(0).MEMBERVALUE       


select 
    {
    [Measures].[Actual Win], 
    [Measures].[StartDate], 
    [Measures].[EndDate]
    } on 0,

    [Customer].[Player Account Number].children on 1

from
(
    select  (
            [Customer].[Player Account Number].&[1040002184]:
            [Customer].[Player Account Number].&[1040002198]
            )  on 0 
    from Ratings
)

where {[Gaming Date].[Full Date].&[20150101]}

重新排列了

[Customer].[Player Account Number]

，以便在每个玩家帐户的上下文中计算日期。希望没问题

编辑

此方法的简化AdWrks版本如下：仍然不太有效：

WITH 
  SET [aSet] AS 
    (EXISTING 
      Head
      (
        NonEmpty
        (
          [Date].[Date].[Date].MEMBERS
         ,[Measures].[Internet Sales Amount]
        )
      )) 
SELECT 
  {[Measures].[Internet Sales Amount]} ON 0
 ,NON EMPTY 
    {[Promotion].[Promotion].MEMBERS * [aSet]} ON 1
FROM [Adventure Works];

您有一个静态集（总是返回相同的成员）。使用

EXISTING

关键字计算当前上下文中的开始和结束时间

with member [Measures].[StartDate] as

    EXISTING    
    HEAD(
            nonempty(
                    [Start Time].[Hour].Children,[Measures].[Actual Win]
                    ) ,1
        ).ITEM(0).ITEM(0).MEMBERVALUE



member [Measures].[EndDate] as
    EXISTING
    TAIL(
            nonempty(
                    [End Time].[Hour].children,[Measures].[Actual Win]
                    ) ,1            
        ).ITEM(0).ITEM(0).MEMBERVALUE       


select 
    {
    [Measures].[Actual Win], 
    [Measures].[StartDate], 
    [Measures].[EndDate]
    } on 0,

    [Customer].[Player Account Number].children on 1

from
(
    select  (
            [Customer].[Player Account Number].&[1040002184]:
            [Customer].[Player Account Number].&[1040002198]
            )  on 0 
    from Ratings
)

where {[Gaming Date].[Full Date].&[20150101]}

重新排列了

[Customer].[Player Account Number]

，以便在每个玩家帐户的上下文中计算日期。希望没问题

编辑

此方法的简化AdWrks版本如下：仍然不太有效：

WITH 
  SET [aSet] AS 
    (EXISTING 
      Head
      (
        NonEmpty
        (
          [Date].[Date].[Date].MEMBERS
         ,[Measures].[Internet Sales Amount]
        )
      )) 
SELECT 
  {[Measures].[Internet Sales Amount]} ON 0
 ,NON EMPTY 
    {[Promotion].[Promotion].MEMBERS * [aSet]} ON 1
FROM [Adventure Works];

通常，第一个日期和最后一个日期都是度量值。如果您只想要这两个玩家的结果，请使用WHERE子句而不是子选择：

WITH 
  MEMBER [Measures].[fDate] AS 
    Head
    (
      NonEmpty
      (
        [Start Time].[Hour].MEMBERS
       ,[Measures].[Actual Win]
      )
    ).Item(0).Item(0).Member_Caption 
  MEMBER [Measures].[lDate] AS 
    Tail
    (
      NonEmpty
      (
        [End Time].[Hour].MEMBERS
       ,[Measures].[Actual Win]
      )
    ).Item(0).Item(0).Member_Caption 
SELECT 
  {
    [Measures].[fDate]
   ,[Measures].[lDate]
   ,[Measures].[Actual Win]
  } ON 0
 ,{[Customer].[Player Account Number].Children} ON 1
FROM Ratings
WHERE 
  ([Gaming Date].[Full Date].&[20150101],
   { [Customer].[Player Account Number].&[1040002184]
    ,[Customer].[Player Account Number].&[1040002198]});

这是一个有效的

AdvWrks

脚本，它完成了您试图实现的任务：

WITH 
  MEMBER [Measures].[firstDate] AS 
    Head
    (
      NonEmpty
      (
        [Date].[Date].[Date].MEMBERS
       ,[Measures].[Internet Sales Amount]
      )
    ).Item(0).Item(0).Member_Caption 
  MEMBER [Measures].[lastDate] AS 
    Tail
    (
      NonEmpty
      (
        [Date].[Date].[Date].MEMBERS
       ,[Measures].[Internet Sales Amount]
      )
    ).Item(0).Item(0).Member_Caption 
SELECT 
  {
    [Measures].[Internet Sales Amount]
   ,[Measures].[firstDate]
   ,[Measures].[lastDate]
  } ON 0
 ,NON EMPTY {[Promotion].[Promotion].MEMBERS} ON 1
FROM [Adventure Works];

如果您希望撤回一个成员而不是使用度量，我认为

GENERATE

函数的工作方式如下AdvWrks示例：

WITH 
  SET [aSet] AS 
    Generate
    (
      [Promotion].[Promotion].MEMBERS
     ,
        [Promotion].[Promotion].CurrentMember
      * 
        Head
        (
          NonEmpty
          (
            [Date].[Date].[Date].MEMBERS
           ,[Measures].[Internet Sales Amount]
          )
        )
    ) 
SELECT 
  {[Measures].[Internet Sales Amount]} ON 0
 ,NON EMPTY 
    {[aSet]} ON 1
FROM [Adventure Works];