Ssas 如何使用mdx查询接收值

如何使用mdx查询接收值。对于此查询，输出值为2.2，但我需要四舍五入到3

WITH MEMBER [AssessmentCouting] AS COUNT(NonEmpty (
                                { 
                                    ( 
                                     ([DimAnchorDate].[Anchor Date].[Anchor Date]),
                                     ([DimAnchorDate].[Calendar Quarter Des].[Calendar Quarter Des]),
                                     ([DimAssessment].[AssessmentText].&[167]&[Care Management Follow up Encounter]),
                                     ([DimAssessment].[QuestionText].[QuestionText]),
                                     ([DimPatient].[Patient Key].[Patient Key]),
                                     ([DimPatient].[Full Name].[Full Name])
                                    )
                                }, 
                        { [Measures].[ProgramAssessmentPatientCnt] }))/10


SELECT [AssessmentCouting] ON 0 
FROM [NavigateCube]

试试看：

WITH MEMBER [AssessmentCouting] AS COUNT(NonEmpty (
                                { 
                                    ( 
                                     ([DimAnchorDate].[Anchor Date].[Anchor Date]),
                                     ([DimAnchorDate].[Calendar Quarter Des].[Calendar Quarter Des]),
                                     ([DimAssessment].[AssessmentText].&[167]&[Care Management Follow up Encounter]),
                                     ([DimAssessment].[QuestionText].[QuestionText]),
                                     ([DimPatient].[Patient Key].[Patient Key]),
                                     ([DimPatient].[Full Name].[Full Name])
                                    )
                                }, 
                        { [Measures].[ProgramAssessmentPatientCnt] }))/10

MEMBER [AssessmentCoutingRounder] AS 
IIF(
    [AssessmentCouting] > Int([AssessmentCouting]), 
    Int([Measures].[AssessmentCouting])+1,
    [Measures].[AssessmentCouting]
)

SELECT {[AssessmentCouting],[AssessmentCoutingRounder]} ON 0 
FROM [NavigateCube]

---

你需要像iff（x>cint（x），x+1，x）这样的东西吗？谢谢你的建议，我使用了这样的IIF（AssessmentCouting>cint（AssessmentCouting），ROUND（AssessmentCouting）+1，AssessmentCouting）@DanyloKorostil，但它应该是IIF，对吗？谢谢你的回答，但当AssessmentCouting=2.8时，它只显示2.8，在这种情况下，我需要指出的是，我以前没有提到过这种行为。您必须使用Int（）而不是Cint（），它会工作得很好。好的，谢谢@DanyloNo problem，如果您的问题得到解决，请将其标记为已回答。我最终将函数成员行数取整为IIF（AssessmentCouting>Cint（AssessmentCouting），round（AssessmentCouting）+1，round（AssessmentCouting））