String 按分隔符展开切片字符串
我想用分隔符“/”展开一个切片字符串 例如,展开以下切片String 按分隔符展开切片字符串,string,go,slice,String,Go,Slice,我想用分隔符“/”展开一个切片字符串 例如,展开以下切片 s := []string{"5/3","9","5/4/1","6"} 应制作单个切片: ["5","9","5","6"] ["5","9","4","6"] ["5","9","1","6"] ["3","9","5","6"] ["3","9","4","6"] ["3","9","1","6"] 我几乎被困在这里了 var c [][]string{} s := []string{"5/3","9","5/4/1","6"}
s := []string{"5/3","9","5/4/1","6"}
应制作单个切片:
["5","9","5","6"] ["5","9","4","6"] ["5","9","1","6"]
["3","9","5","6"] ["3","9","4","6"] ["3","9","1","6"]
我几乎被困在这里了
var c [][]string{}
s := []string{"5/3","9","5/4/1","6"}
for _, v := range s {
combos := strings.Split(v, "/")
for _, combo := range combos {
}
}
撇开运行时间不谈,您可以通过递归实现这一点
func Perm(digits [][]string) (perm [][]string) {
if len(digits) == 0 || len(digits) == 1 {
return digits
}
nextDigits := Perm(digits[1:])
for _, digit := range digits[0] {
for _, next := range nextDigits {
cat := append([]string{digit}, next...)
perm = append(perm, cat)
}
}
return perm
}
FYI,你在这里寻找的术语是“扩展”。你真的想让这里的人做你的家庭作业吗?我投票结束这个问题,因为家庭作业是离题的。@Volker:Read.@Volker我不知道你说的家庭作业问题是什么意思。我被塞米拉在下面的回答中解释的逻辑所束缚。我可以在其他编程语言中多次看到类似的问题。另外,我不知道有多少大学课程是基于golang来进行家庭作业的!