Swagger 如何在定义中重用招摇过市定义？

代码如下：

definitions:
  Result:
    type: object
    properties:
      code:
        type: integer
        format: int32
      message:
        type: string
  FindUID:
    type: object
    properties:
      code:
        type: integer
        format: int32
      message:
        type: string
      data:
        type: object
        properties:
          uid:
            type: integer
            format: int64
  FindUsername:
    type: object
    properties:
      code:
        type: integer
        format: int32
      message:
        type: string
      data:
        type: object
        properties:
          username:
            type: string

---

如您所见，

FindUID

和

FindUsername

的第一部分与

Result

相同。如何用

Result

替换那些重复的代码？

您可以使用

allOf

组合定义，下面是一个完整的示例，其中在FindUID和FindUsername中使用Result：

swagger: '2.0'
info:
  description: Example API Description
  title: Example Title
  version: 1.0.0
paths: {}
definitions:
  Result:
    type: object
    properties:
      code:
        type: integer
        format: int32
      message:
        type: string
  FindUID:
    allOf:
      - $ref: "#/definitions/Result"
      - type: object
        properties:
          data:
            type: object
            properties:
              uid:
                type: integer
                format: int64
  FindUsername:
    allOf:
      - $ref: "#/definitions/Result"
      - type: object
        properties:
          data:
            type: object
            properties:
              username:
                type: string

更多信息请参见：（披露：我编写了本教程）