swift 3问题，CVarArg被多次通过

我在swift 3中有以下代码：

 class StringUtility {

  static func Localizer(tableName: String?) -> (_ key: String, _ params: CVarArg...) -> String {
    return { (key: String, params: CVarArg...) in

      let content = NSLocalizedString(key, tableName: tableName, comment: "")

      if params.isEmpty {
        return content
      }

      print(params) ->>>>>> this prints [[[Wells Fargo]]]
      return NSString.init((format: content, arguments: getVaList(params))) as String
    }
  }
}

func localizationHelper(tableName: String, key: String, params: CVarArg...) -> String {
  let t = StringResourceUtility.Localizer(tableName: tableName)
  print(params) - >>>>>>>>>> this prints [[Wells Fargo]]
  return t(key, params)
}

如果您在上述两个函数中看到print语句，则每次在函数中传递CVarArg时都会追加[]，从而导致输出错误的本地化字符串

1） CVarArg不能像上面的代码那样多次传递？

---

2） 如何解决此问题？

不能将变量参数列表传递给另一个函数，必须 必须传递一个

CVaListPointer

。此外，还应使用Valist

用于代替
getVaList
：

class StringResourceUtility {

    static func Localizer(tableName: String?) -> (_ key: String, _ params: CVaListPointer) -> String {
        return { (key: String, params: CVaListPointer) in
            let content = NSLocalizedString(key, tableName: tableName, comment: "")
            return NSString(format: content, arguments: params) as String
        }
    }
}

func localizationHelper(tableName: String, key: String, params: CVarArg...) -> String {
    let t = StringResourceUtility.Localizer(tableName: tableName)
    return withVaList(params) { t(key, $0) } 
}

例如：

let s = localizationHelper(tableName: "table", key: "%@ %@", params: "Wells", "Fargo")
print(s) // Wells Fargo

这是一个关于在Swift中实现健壮架构的本地化的示例