Swift ABPEOPLEPICKERNAVIGATION控制器应在选择人员后继续

由于我将我的xcode 6版本更新为beta 3，我在AddressBookUI方面遇到了很多问题

阅读Apple API文档时，我看到了以下功能：

func peoplePickerNavigationController(peoplePicker: ABPeoplePickerNavigationController!, shouldContinueAfterSelectingPerson person: ABRecordRef!) -> Bool {}

在IOS 8中被弃用。如何将此方法更新为正确的版本

在此方法中，我有以下代码：

var dadosContato: Dictionary<String, String> = ["firstName": "", "lastName": "","mobileNumber": "", "homeNumber": ""]

//NOME
var firstName: Unmanaged<AnyObject> = ABRecordCopyValue(person, kABPersonFirstNameProperty)
dadosContato["firstName"] = firstName.takeRetainedValue() as? String

//SOBRENOME
var lastName: Unmanaged<AnyObject> = ABRecordCopyValue(person, kABPersonLastNameProperty)
dadosContato["lastName"] = lastName.takeRetainedValue() as? String

//RECEBENDO OS TELEFONES
var phones: ABMultiValueRef = ABRecordCopyValue(person, kABPersonPhoneProperty).takeUnretainedValue() as ABMultiValueRef

for var index = 0; index < ABMultiValueGetCount(phones); ++index{
    let currentPhoneLabel = ABMultiValueCopyLabelAtIndex(phones, index).takeUnretainedValue() as CFStringRef as String
    let currentPhoneValue = ABMultiValueCopyValueAtIndex(phones, index).takeUnretainedValue() as CFStringRef as String

    if currentPhoneLabel == kABPersonPhoneMobileLabel {
        dadosContato["mobileNumber"] = currentPhoneValue
    }

    if currentPhoneLabel == kABHomeLabel {
        dadosContato["homeNumber"] = currentPhoneValue
    }

}

---

你有我没有的一半答案。 在手机中使用代码之前，您需要执行检查：

            let phoneV: ABMultiValueRef = ABRecordCopyValue(record, kABPersonPhoneProperty).takeUnretainedValue() as ABMultiValueRef

            if ABMultiValueGetCount(phoneV) > 0
            {
                var phones: ABMultiValueRef = ABRecordCopyValue(contactPerson, kABPersonPhoneProperty).takeUnretainedValue() as ABMultiValueRef

                for var index = 0; index < ABMultiValueGetCount(phones); ++index{
                    let currentPhoneLabel = ABMultiValueCopyLabelAtIndex(phones, index).takeUnretainedValue() as CFStringRef as String
                    let currentPhoneValue = ABMultiValueCopyValueAtIndex(phones, index).takeUnretainedValue() as CFStringRef as String

                    if currentPhoneLabel == kABPersonPhoneMobileLabel {
                        println(currentPhoneValue)
                    }

                    if currentPhoneLabel == kABHomeLabel {
                        println(currentPhoneValue)
                    }

                }                    
            }

让phoneV:ABMultiValueRef=ABRecordCopyValue（记录，kabbersonphoneproperty）。将unrepainedvalue（）作为ABMultiValueRef
如果ABMultiValueGetCount（phoneV）>0
{
var phones:ABMultiValueRef=ABRecordCopyValue（contactPerson，KabbersonPhoneProperty）。将unrepainedValue（）作为ABMultiValueRef
对于var index=0；index

我认为这是Swift编译器中的一个错误。我遇到了同样的问题。希望苹果能尽快修复它。一个临时的解决方法是用Objective-C编写通讯簿代码（并有一个返回数据结构的方法），然后Swift代码将调用该代码。选择Person后，该函数应继续？现在在ios 8上使用它的正确方法是什么？我在这里回答了这个问题：谢谢，你的解决方案适合我！！！！

            let phoneV: ABMultiValueRef = ABRecordCopyValue(record, kABPersonPhoneProperty).takeUnretainedValue() as ABMultiValueRef

            if ABMultiValueGetCount(phoneV) > 0
            {
                var phones: ABMultiValueRef = ABRecordCopyValue(contactPerson, kABPersonPhoneProperty).takeUnretainedValue() as ABMultiValueRef

                for var index = 0; index < ABMultiValueGetCount(phones); ++index{
                    let currentPhoneLabel = ABMultiValueCopyLabelAtIndex(phones, index).takeUnretainedValue() as CFStringRef as String
                    let currentPhoneValue = ABMultiValueCopyValueAtIndex(phones, index).takeUnretainedValue() as CFStringRef as String

                    if currentPhoneLabel == kABPersonPhoneMobileLabel {
                        println(currentPhoneValue)
                    }

                    if currentPhoneLabel == kABHomeLabel {
                        println(currentPhoneValue)
                    }

                }                    
            }