Alamofire API连接和Swift

我对EatStreet API的AlamoFire请求有问题。我有一个API密钥，并且正确导入了Alamofire

下面是他们将为您创建API URL字符串的网站链接

尽管如此，我还是没有成功

这是示例字符串

curl -X GET \
 -H 'X-Access-Token: __API_EXPLORER_AUTH_KEY__' \
 'https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.718293&longitude=-74.002276&method=pickup&pickup-radius=2'

下面是我的api和Alamofire请求的示例代码。对于结果的值，它不断返回false。谢谢你的帮助

import UIKit
import Firebase
import FirebaseDatabase

import FirebaseAuth
import Alamofire
import SwiftyJSON

class ViewController: UIViewController {

override func viewDidLoad() {
    super.viewDidLoad()

    // Do any additional setup after loading the view, typically from a nib.
    let tap: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(LoginViewController.dismissKeyboard))

    //Uncomment the line below if you want the tap not not interfere and cancel other interactions.
    tap.cancelsTouchesInView = false

    view.addGestureRecognizer(tap)

    let apiToContact = "\\ -H 'X-Access-Token: f6565a0360167144' \\'https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.718293&longitude=-74.002276&method=pickup&pickup-radius=2'"
    Alamofire.request(apiToContact).validate().responseJSON() { response in
        switch response.result {
        case .success:
            if let value = response.result.value {
                let json = JSON(value)

                // Do what you need to with JSON here!
                // The rest is all boiler plate code you'll use for API requests
                print(json)

            }
        case .failure(let error):
            print(error)
        }
    }


}


//Calls this function when the tap is recognized.
func dismissKeyboard() {
    //Causes the view (or one of its embedded text fields) to resign the first responder status.
    view.endEditing(true)
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}


}

如中所述，您应该发送带有标头参数的请求

let headers: HTTPHeaders = [
    "X-Access-Token": "API_EXPLORER_AUTH_KEY"
]

let url = "https://api.eatstreet.com/publicapi/v1/restaurant/search?latitude=40.718293&longitude=-74.002276&method=pickup&pickup-radius=2"

Alamofire.request(url, headers: headers).responseJSON { response in
    print(response)
}

---

另一个解决方案如下所示。在这里，查询参数将自动生成并附加到URL。这种方法可以防止查询参数中的某些特殊字符转义。试试下面的方法

 func sendRequest() {
    let headers = ["X-Access-Token":"eatstreetToken"]
    let parameters:[String:Any] = ["latitude":40.718293,"longitude":-74.002276, "method":"pickup","pickup-radius":2]
    let apiToContact = "https://api.eatstreet.com/publicapi/v1/restaurant/search"

    let request = Alamofire.request(apiToContact, method: .get, parameters: parameters, encoding: URLEncoding.queryString, headers: headers)
    request.validate().responseJSON() { response in
        print(response.response?.url ?? "malformed url")
        switch response.result {
        case .success(let value):
              print(value)
        case .failure(let error):
            print(error)
        }
    }
}

---

如果我希望编码为jsondoesn，而不是像eatstreet为该字符串返回的那样，我只是通过在eatstreet开发者门户上创建新帐户来尝试上面的代码，并且在我的控制台上打印的响应是correct@HiDungLing太好了，请记为正确答案；）