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Swift 如何在URL中使用特殊字符\n_Swift_Url_Post_Swift3 - Fatal编程技术网

Swift 如何在URL中使用特殊字符\n

Swift 如何在URL中使用特殊字符\n,swift,url,post,swift3,Swift,Url,Post,Swift3,我有一个发帖请求: init (url: String,arg: String) { self.responseString = nil var request = URLRequest(url: URL(string: url)!) request.httpMethod = "POST" let postString = arg request.httpBody = postString.data(using: .utf8) let task =

我有一个发帖请求:

init (url: String,arg: String) {
    self.responseString = nil
    var request = URLRequest(url: URL(string: url)!)
    request.httpMethod = "POST"
    let postString = arg
    request.httpBody = postString.data(using: .utf8)
    let task = URLSession.shared.dataTask(with: request) {
        data, response, error in
        guard let data = data, error == nil else {                                                 
            print("error=\(error)")
            self.responseString = nil
            return
        }
        if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {           //
            self.responseString = nil
        } else {
        self.responseString = String(data: data, encoding: .utf8)
        }
    }
    task.resume()
    }
当arg有字符\n时,一半arg文本丢失。如何解决这个问题

strUrl = strUrl.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed)!

let url = URL.init(string: strUrl)

let requestURL = URLRequest(url: url!)
  • 您需要添加addingPercentEncoding(withAllowedCharacters:CharacterSet.UrlQueryLowed)方法以允许URL查询
  • 您需要添加addingPercentEncoding(withAllowedCharacters:CharacterSet.UrlQueryLowed)方法以允许URL查询

我看不出换行符在URL字符串中有何意义,但通常可以对URL字符串进行百分比转义:
let ecaped=urlString.addingPercentEncoding(withAllowedCharacters:.urlHostAllowed)
。我看不到换行符在URL字符串中有何意义,但一般来说,您可以对url字符串进行百分比转义:
let ecaped=urlString.addingPercentEncoding(使用AllowedCharacters:.urlHostAllowed)