使用SwiftyJSON解析comlpex JSON

使用SwiftyJSON解析comlpex JSON,swift,swifty-json,Swift,Swifty Json,我一次又一次地尝试从这个JSON解析缩略图路径地址 "data":{ "offset":0, "limit":20, "total":1491, "count":20, "results":[ { "id":1011334, "name":"3-D Man", "description":

我一次又一次地尝试从这个JSON解析缩略图路径地址

"data":{ 
        "offset":0,
        "limit":20,
        "total":1491,
        "count":20,
        "results":[  
            {  
                "id":1011334,
                "name":"3-D Man",
                "description":"",
                "modified":"2014-04-29T14:18:17-0400",
                "thumbnail":{  
                    "path":"http://i.annihil.us/u/prod/marvel/i/mg/c/e0/535fecbbb9784",
                    "extension":"jpg"
                },
但我似乎找不到我问题的答案。我正在这样做:

 for (key, subJson) in json["data", "results", "thumbnail", "path"] {
                    if let imagePath = subJson["path"].string {
                        print(imagePath)
                        let finalImagePath = imagePath + "somestring with my priv key and pub key"
                        print(finalImagePath)
                    }
                }
我这样做是为了减少字符的名称和id,如下所示:

for (key, subJson) in json["data"]["results"] {
                    if let name = subJson["name"].string, let id = subJson["id"].int {
                        cardInfo.append(CardInfo(id: id, name: name))
//                        print(cardInfo)
                    }
                }
它工作得非常完美,但对于缩略图,我已经在网上搜索了一段时间,试图自己找出答案

如果有人能给我答案,我将不胜感激,我已经挣扎了这么久了

提前感谢

您可以试试

if let item = json["data"]["results"].array?.first , let path = item["thumbnail"]["path"].string  { 
   print(path) 
}

总的来说

for (_, subJson) in json["data"]["results"] {
   if let path = subJson["thumbnail"]["path"].string {
      print(path) 
   }
}