Swift 如何在没有segue的情况下将数据从UITableView传递到UIViewController

我需要将

UITableView

中的行标题传递给我的

ViewController

。我在故事板中没有VC（我是通过代码创建的）。所以我不能用segue

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {

   let cell = tableView.cellForRow(at: indexPath) as! UITableViewCell


    cell.textLabel?.textColor = UIColor(red: 0, green: 122/255, blue: 1, alpha: 1)
    cell.textLabel?.tintColor = UIColor(red: 0, green: 122/255, blue: 1, alpha: 1)

        var titleOfFood = String()
        if searching == true {
           titleOfFood = searchedFoods[indexPath.row].title
            cell.textLabel?.textColor = UIColor(red: 0, green: 122/255, blue: 1, alpha: 1)
             print(titleOfFood)
        } else {
            titleOfFood = foods[indexPath.row].title
            cell.textLabel?.textColor = UIColor(red: 0, green: 122/255, blue: 1, alpha: 1)
             print(titleOfFood)
        }

    let controller = EatenFoodViewController()
    let transitionDelegate = SPStorkTransitioningDelegate()
    controller.transitioningDelegate = transitionDelegate
    controller.modalPresentationStyle = .custom
    //controller.delegate = self
    transitionDelegate.customHeight = 620
    transitionDelegate.showIndicator = false
    self.present(controller, animated: true, completion: nil)
}

---

我需要将

标题食品

传递给

EatenFoodViewController

您不需要一个序列就可以将数据发送到目标vc，您只需这样做即可

controller.titleOfFood = arr[indexPath.row].title // assuming you have an array of models 

或

controller.titleOfFood = cell.textLabel!.text!

---

---

如何从UITableView向TitleOfood行发送行标题，我无法理解var titleOfood=”“。这是什么。如何处理：）请参见编辑

var titleofood=“

是应该接收发送值的变量，您应该在目标vc中使用它

class EatenFoodViewController:UIViewController {
   var titleOfFood = ""
}