Swift 快速排序数组

我想对数组进行排序

像这样：

let elements = ["S","A","C","C","T","E","E","E","F","S","S","A","A","C"]

我试过这么做

var currentElement = ""
var newElements:[String] = []
for element in elements {
    if currentElement != element{
        currentElement = element
        newElements.append(element)
    }
}

但是

打印[“S”、“A”、“C”、“T”、“E”、“F”、“S”、“A”、“C”]

---

如何将其排序到

[“A”、“C”、“E”、“F”、“S”、“T”]

您要做的是删除重复项，然后对其进行排序，对吗

您可以将其转换为

集合

，然后调用

排序（）

：

---

应该使用ComparisonResult按字母顺序对数组进行排序，因为Set（elements）.sorted（）和小写字符会导致排序结果错误

var elements = ["S","A","C","C","T","E","E","E","F","S","S","A","A","C"]

elements = elements.sorted { $0.localizedCaseInsensitiveCompare($1) == ComparisonResult.orderedAscending }

//the output["A", "A", "A", "C", "C", "C", "E", "E", "E", "F", "S", "S", "S", "T"]

---

Wtf，你甚至没有在你的if条件下排序任何东西，它甚至没有尝试排序任何东西，你只是在抑制重复！在我看来，这很像是一种你不想做的家庭作业，回去工作，在谷歌上搜索。首先：唯一值：然后排序：你救了我的命，谢谢！！

["A", "A", "A", "C", "C", "C", "E", "E", "E", "F", "S", "S", "S", "T"]

let elements = ["S","A","C","C","T","E","E","E","F","S","S","A","A","C"]
let newElements = Set(elements).sorted() // ["A", "C", "E", "F", "S", "T"]

var elements = ["S","A","C","C","T","E","E","E","F","S","S","A","A","C"]

elements = elements.sorted { $0.localizedCaseInsensitiveCompare($1) == ComparisonResult.orderedAscending }

//the output["A", "A", "A", "C", "C", "C", "E", "E", "E", "F", "S", "S", "S", "T"]