Swift2 架构x86_64的未定义符号，用于带有Alamofire.Request的扩展

我为

Alamofire.Response

创建了一个协议，然后像这样扩展它

import Alamofire
public protocol MyResponseType {
    typealias Value
    typealias Error: ErrorType
    var request: NSURLRequest? { get }
    var response: NSHTTPURLResponse? { get }
    var data: NSData? { get }
    var result: Alamofire.Result<Value, Error> { get }
    init(request: NSURLRequest?, response: NSHTTPURLResponse?, data: NSData?, result: Alamofire.Result<Value, Error>, timeline: Alamofire.Timeline)
}

extension Alamofire.Response: MyResponseType {}

导入Alamofire
公共协议MyResponseType{
类型别名值
typealias错误：ErrorType
var请求：NSURLRequest？{get}
var响应：NSHTTPURLResponse？{get}
变量数据：NSData？{get}
var result:Alamofire.result{get}
初始化（请求：NSURLRequest？，响应：NSHTTPURLResponse？，数据：NSData？，结果：Alamofire.result，时间线：Alamofire.timeline）
}
扩展Alamofire.Response:MyResponseType{}

构建过程通过了，但当涉及到链接时，它失败了。错误来了

Undefined symbols for architecture x86_64:
  "Alamofire.Response.data.getter : __ObjC.NSData?", referenced from:
      protocol witness for wtftest. MyResponseType.data.getter : __ObjC.NSData? in conformance <A, B where B: Swift.ErrorType> Alamofire.Response<A, B> : wtftest. MyResponseType in wtftest in ViewController.o
  "Alamofire.Response.result.getter : Alamofire.Result<A, B>", referenced from:
      protocol witness for wtftest. MyResponseType.result.getter : Alamofire.Result<A.Value, A.Error> in conformance <A, B where B: Swift.ErrorType> Alamofire.Response<A, B> : wtftest.ProducerResponseType in wtftest in ViewController.o
  "Alamofire.Response.request.getter : __ObjC.NSURLRequest?", referenced from:
      protocol witness for wtftest. MyResponseType.request.getter : __ObjC.NSURLRequest? in conformance <A, B where B: Swift.ErrorType> Alamofire.Response<A, B> : wtftest. MyResponseType in wtftest in ViewController.o
  "Alamofire.Response.response.getter : __ObjC.NSHTTPURLResponse?", referenced from:
      protocol witness for wtftest. MyResponseType.response.getter : __ObjC.NSHTTPURLResponse? in conformance <A, B where B: Swift.ErrorType> Alamofire.Response<A, B> : wtftest.ProducerResponseType in wtftest in ViewController.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

架构x86_64的未定义符号： “Alamofire.Response.data.getter:\uu ObjC.NSData？”，引用自： wtftest的协议见证。MyResponseType.data.getter:\uu ObjC.NSData？响应：wtftest。ViewController.o中wtftest中的MyResponseType “Alamofire.Response.result.getter:Alamofire.result”，引用自： wtftest的协议见证。MyResponseType.result.getter:Alamofire.result符合Alamofire.Response:wtftest.ProducerResponseType in wtftest in ViewController.o “Alamofire.Response.request.getter:\uu ObjC.NSURLRequest？”，引用自： wtftest的协议见证。MyResponseType.request.getter:\uu ObjC.NSURLRequest？响应：wtftest。ViewController.o中wtftest中的MyResponseType “Alamofire.Response.Response.getter:\uu ObjC.NSHTTPURLResponse？”，引用自： wtftest的协议见证。MyResponseType.response.getter:\uu ObjC.nshtpurlResponse？一致性中的Alamofire.Response:wtftest.ProducerResponseType在ViewController.o中的wtftest中 ld:找不到架构x86_64的符号 叮当声：错误：链接器命令失败，退出代码为1（使用-v查看调用）

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这是斯威夫特的虫子吗？还是我做错了什么？

请提及

ProducerResponseType

too@SohilR.Memon对不起，

ProducerResponseType

实际上是我的responsetype，忘了修改它了，关于这一点，我的头也撞到墙上了。仅在瞄准模拟器时失败，但设备仍能正常工作。