Swift3 Swift 2.3至Swift 3.0获取成员的模糊参考错误'；加入'；

我正在将swift 2.3转换为swift 3.0

Swift 2.3代码：

extension ContextDidSaveNotification: CustomDebugStringConvertible {
    public var debugDescription: String {
        var components = [notification.name]
        components.append(managedObjectContext.description)
        for (name, set) in [("inserted", insertedObjects), ("updated", updatedObjects), ("deleted", deletedObjects)] {
            let all = set.map { $0.objectID.description }.joinWithSeparator(", ")
            components.append("\(name): {\(all)}")
        }
        return components.joinWithSeparator(" ")
    }
}

extension ContextDidSaveNotification: CustomDebugStringConvertible {
    public var debugDescription: String {
        var components = [notification.name]
        components.append(Notification.Name(rawValue: managedObjectContext.description))
        for (name, set) in [("inserted", insertedObjects), ("updated", updatedObjects), ("deleted", deletedObjects)] {
            let all = set.map { $0.objectID.description }.joined(separator: ", ")
            components.append(Notification.Name(rawValue: "\(name): {\(all)}"))
        }
        return components.joined(separator: " ")
    }
}

Swift 3.0代码：

extension ContextDidSaveNotification: CustomDebugStringConvertible {
    public var debugDescription: String {
        var components = [notification.name]
        components.append(managedObjectContext.description)
        for (name, set) in [("inserted", insertedObjects), ("updated", updatedObjects), ("deleted", deletedObjects)] {
            let all = set.map { $0.objectID.description }.joinWithSeparator(", ")
            components.append("\(name): {\(all)}")
        }
        return components.joinWithSeparator(" ")
    }
}

extension ContextDidSaveNotification: CustomDebugStringConvertible {
    public var debugDescription: String {
        var components = [notification.name]
        components.append(Notification.Name(rawValue: managedObjectContext.description))
        for (name, set) in [("inserted", insertedObjects), ("updated", updatedObjects), ("deleted", deletedObjects)] {
            let all = set.map { $0.objectID.description }.joined(separator: ", ")
            components.append(Notification.Name(rawValue: "\(name): {\(all)}"))
        }
        return components.joined(separator: " ")
    }
}

但是我得到了一个错误：对于Swift 3.0代码中的lase返回，对memeber'joined（）'的引用不明确

如何解决这个问题？我做了很多研究，但没有找到有效的解决方案

感谢

加入（分隔符：）

是为

数组

声明的，而不是

数组

：

---

正如@vadian指出的，

Notification.Name

并不等同于

String

，因此您需要首先转换数组。这应该起作用：

components
  .map({ $0.rawValue })
  .joined(separator: " ")

---

尝试在组件var初始化中显式声明类型。

Notification.Name

是Swift 3中的一个结构，而不是字符串，这不是

joined（）

所期望的