Terraform 从本地列表中获取值

Terraform 从本地列表中获取值,terraform,terraform-provider-aws,Terraform,Terraform Provider Aws,我正在尝试使用terraform标记docker swarm实例 我将变量和局部变量定义为 变量。tf variable "instance_count" { default = "3" } variable "instance_type" { default = "t2.micro" } variable "aws_region" { default = "us-east-

我正在尝试使用terraform标记docker swarm实例 我将变量和局部变量定义为 变量。tf

variable "instance_count" {
  default = "3"
}
variable "instance_type" {
  default = "t2.micro"
}
variable "aws_region" {
  default = "us-east-1"
}
variable "ami" {
  default = "ami-09e67e426f25ce0d7"
}
variable "host_name" {
  type    = map(number)
  default = {
    "Manager" = 1
    "Worker" = 2
  }
}

resource "aws_instance" "swarm_instance" {
  count           = var.instance_count
  ami             = var.ami
  instance_type   = var.instance_type
  key_name        = aws_key_pair.dockerswarm.key_name

  tags = {
    Name = "Swarm_Instance-${count.index + 1}"
  }
   tags = {
    Name = "${local.expanded_names}"
  }
locals {
  expanded_names = {
    for name, count in var.host_name : name => [
      for i in range(count) : format("%s-%02d", name, i+1)
    ]
  }
}
当我参考这个列表的每个值,将其作为标记分配给ec2实例时,如下所示 ec2instance.tf

variable "instance_count" {
  default = "3"
}
variable "instance_type" {
  default = "t2.micro"
}
variable "aws_region" {
  default = "us-east-1"
}
variable "ami" {
  default = "ami-09e67e426f25ce0d7"
}
variable "host_name" {
  type    = map(number)
  default = {
    "Manager" = 1
    "Worker" = 2
  }
}

resource "aws_instance" "swarm_instance" {
  count           = var.instance_count
  ami             = var.ami
  instance_type   = var.instance_type
  key_name        = aws_key_pair.dockerswarm.key_name

  tags = {
    Name = "Swarm_Instance-${count.index + 1}"
  }
   tags = {
    Name = "${local.expanded_names}"
  }
locals {
  expanded_names = {
    for name, count in var.host_name : name => [
      for i in range(count) : format("%s-%02d", name, i+1)
    ]
  }
}
地形抱怨
local.expanded_name是具有两个属性的对象
我尝试使用
${local.expanded_names.value}
,但它抱怨
对象没有名为“value”的属性。

因此,当值属性在terraform中不可用时,如何从列表中检索值。

标记应该是字符串,在您的情况下,我将使用
jsonecode
从您正在构建的对象中获取字符串,请参见下面的示例代码

variable "host_name" {
  type    = map(number)
  default = {
    "Manager" = 1
    "Worker" = 2
  }
}

locals {
  expanded_names = jsonencode({
    for name, count in var.host_name : name => [
      for i in range(count) : format("%s-%02d", name, i+1)
    ]
  })
}

provider "aws" {
  region = "us-east-1"
}

resource "aws_instance" "instance" {
  ami           = "ami-1c761163"
  instance_type = "r5.large"

  tags = {
    Terraformed = "true"
    Name        = local.expanded_names
  }
}
如果我们在上面运行一个地形图,我们得到的结果如下:

Terraform will perform the following actions:

  # aws_instance.instance will be created
  + resource "aws_instance" "instance" {
      + ami                                  = "ami-1c761163"
      ...
      + instance_state                       = (known after apply)
      + instance_type                        = "r5.large"
      ...
      + subnet_id                            = (known after apply)
      + tags                                 = {
          + "Name"        = jsonencode(
                {
                  + Manager = [
                      + "Manager-01",
                    ]
                  + Worker  = [
                      + "Worker-01",
                      + "Worker-02",
                    ]
                }
            )
          + "Terraformed" = "true"
        }



或者您想做的是创建一个名称数组:

  • 经理-01
  • 工人-01
  • 工人-02
然后将其用作实例名称。。。如果在这种情况下,扩展的_名称不应该是对象
{}
,而应该是数组
[]
,那么我们使用它来代替您的计数,请参见下面的代码示例:

variable "host_name" {
  type    = map(number)
  default = {
    "Manager" = 1
    "Worker" = 2
  }
}

locals {
  expanded_names = flatten([
    for name, count in var.host_name : [
      for i in range(count) : format("%s-%02d", name, i+1)
    ]
  ])
}

provider "aws" {
  region = "us-east-1"
}

resource "aws_instance" "instance" {
  for_each = toset(local.expanded_names)

  ami           = "ami-1c761163"
  instance_type = "r5.large"

  tags = {
    Terraformed = "true"
    Name        = each.value
  }
}
以及输出的地形平面图:

Terraform will perform the following actions:

  # aws_instance.instance["Manager-01"] will be created
  + resource "aws_instance" "instance" {
      + ami                                  = "ami-1c761163"
      ...
      + tags                                 = {
          + "Name"        = "Manager-01"
          + "Terraformed" = "true"
        }
      ...
    }

  # aws_instance.instance["Worker-01"] will be created
  + resource "aws_instance" "instance" {
      + ami                                  = "ami-1c761163"
      ...
      + tags                                 = {
          + "Name"        = "Worker-01"
          + "Terraformed" = "true"
        }
      ...
    }

  # aws_instance.instance["Worker-02"] will be created
  + resource "aws_instance" "instance" {
      + ami                                  = "ami-1c761163"
      ...
      + tags                                 = {
          + "Name"        = "Worker-02"
          + "Terraformed" = "true"
        }
      ...
    }

Plan: 3 to add, 0 to change, 0 to destroy.

您如何迭代
扩展的\u名称
本地?理想情况下,您的问题应形成一个表格,以便更容易理解如何重现您的特定问题,并指出您可能犯了错误的地方。您使用
标记的完整代码是什么?我已根据注释更新了上面的代码。我想知道你名字的价值。谢谢你的回答@helder sepulveda。我已经按照您的建议进行了操作,但无法从要用作实例标记的编码json字符串中检索值。请看@RaviKumarCH你的形象看起来不错,你到底期待什么。。。如果我们需要一个字符串并将其编码为json,那么扩展的_名称就是一个对象that@RaviKumarCH请参阅我对以上答案的编辑。。。我认为您希望将扩展的_名称作为一个数组,然后在名称上循环。非常好,这很管用。。再次感谢您@helder sepulveda