Terraform 从本地列表中获取值
我正在尝试使用terraform标记docker swarm实例 我将变量和局部变量定义为 变量。tfTerraform 从本地列表中获取值,terraform,terraform-provider-aws,Terraform,Terraform Provider Aws,我正在尝试使用terraform标记docker swarm实例 我将变量和局部变量定义为 变量。tf variable "instance_count" { default = "3" } variable "instance_type" { default = "t2.micro" } variable "aws_region" { default = "us-east-
variable "instance_count" {
default = "3"
}
variable "instance_type" {
default = "t2.micro"
}
variable "aws_region" {
default = "us-east-1"
}
variable "ami" {
default = "ami-09e67e426f25ce0d7"
}
variable "host_name" {
type = map(number)
default = {
"Manager" = 1
"Worker" = 2
}
}
resource "aws_instance" "swarm_instance" {
count = var.instance_count
ami = var.ami
instance_type = var.instance_type
key_name = aws_key_pair.dockerswarm.key_name
tags = {
Name = "Swarm_Instance-${count.index + 1}"
}
tags = {
Name = "${local.expanded_names}"
}
locals {
expanded_names = {
for name, count in var.host_name : name => [
for i in range(count) : format("%s-%02d", name, i+1)
]
}
}
当我参考这个列表的每个值,将其作为标记分配给ec2实例时,如下所示
ec2instance.tf
variable "instance_count" {
default = "3"
}
variable "instance_type" {
default = "t2.micro"
}
variable "aws_region" {
default = "us-east-1"
}
variable "ami" {
default = "ami-09e67e426f25ce0d7"
}
variable "host_name" {
type = map(number)
default = {
"Manager" = 1
"Worker" = 2
}
}
resource "aws_instance" "swarm_instance" {
count = var.instance_count
ami = var.ami
instance_type = var.instance_type
key_name = aws_key_pair.dockerswarm.key_name
tags = {
Name = "Swarm_Instance-${count.index + 1}"
}
tags = {
Name = "${local.expanded_names}"
}
locals {
expanded_names = {
for name, count in var.host_name : name => [
for i in range(count) : format("%s-%02d", name, i+1)
]
}
}
地形抱怨
local.expanded_name是具有两个属性的对象
我尝试使用${local.expanded_names.value}
,但它抱怨对象没有名为“value”的属性。
因此,当值属性在terraform中不可用时,如何从列表中检索值。标记应该是字符串,在您的情况下,我将使用jsonecode
从您正在构建的对象中获取字符串,请参见下面的示例代码
variable "host_name" {
type = map(number)
default = {
"Manager" = 1
"Worker" = 2
}
}
locals {
expanded_names = jsonencode({
for name, count in var.host_name : name => [
for i in range(count) : format("%s-%02d", name, i+1)
]
})
}
provider "aws" {
region = "us-east-1"
}
resource "aws_instance" "instance" {
ami = "ami-1c761163"
instance_type = "r5.large"
tags = {
Terraformed = "true"
Name = local.expanded_names
}
}
如果我们在上面运行一个地形图,我们得到的结果如下:
Terraform will perform the following actions:
# aws_instance.instance will be created
+ resource "aws_instance" "instance" {
+ ami = "ami-1c761163"
...
+ instance_state = (known after apply)
+ instance_type = "r5.large"
...
+ subnet_id = (known after apply)
+ tags = {
+ "Name" = jsonencode(
{
+ Manager = [
+ "Manager-01",
]
+ Worker = [
+ "Worker-01",
+ "Worker-02",
]
}
)
+ "Terraformed" = "true"
}
或者您想做的是创建一个名称数组:
- 经理-01
- 工人-01
- 工人-02
然后将其用作实例名称。。。如果在这种情况下,扩展的_名称不应该是对象{}
,而应该是数组[]
,那么我们使用它来代替您的计数,请参见下面的代码示例:
variable "host_name" {
type = map(number)
default = {
"Manager" = 1
"Worker" = 2
}
}
locals {
expanded_names = flatten([
for name, count in var.host_name : [
for i in range(count) : format("%s-%02d", name, i+1)
]
])
}
provider "aws" {
region = "us-east-1"
}
resource "aws_instance" "instance" {
for_each = toset(local.expanded_names)
ami = "ami-1c761163"
instance_type = "r5.large"
tags = {
Terraformed = "true"
Name = each.value
}
}
以及输出的地形平面图:
Terraform will perform the following actions:
# aws_instance.instance["Manager-01"] will be created
+ resource "aws_instance" "instance" {
+ ami = "ami-1c761163"
...
+ tags = {
+ "Name" = "Manager-01"
+ "Terraformed" = "true"
}
...
}
# aws_instance.instance["Worker-01"] will be created
+ resource "aws_instance" "instance" {
+ ami = "ami-1c761163"
...
+ tags = {
+ "Name" = "Worker-01"
+ "Terraformed" = "true"
}
...
}
# aws_instance.instance["Worker-02"] will be created
+ resource "aws_instance" "instance" {
+ ami = "ami-1c761163"
...
+ tags = {
+ "Name" = "Worker-02"
+ "Terraformed" = "true"
}
...
}
Plan: 3 to add, 0 to change, 0 to destroy.
您如何迭代扩展的\u名称
本地?理想情况下,您的问题应形成一个表格,以便更容易理解如何重现您的特定问题,并指出您可能犯了错误的地方。您使用标记的完整代码是什么?我已根据注释更新了上面的代码。我想知道你名字的价值。谢谢你的回答@helder sepulveda。我已经按照您的建议进行了操作,但无法从要用作实例标记的编码json字符串中检索值。请看@RaviKumarCH你的形象看起来不错,你到底期待什么。。。如果我们需要一个字符串并将其编码为json,那么扩展的_名称就是一个对象that@RaviKumarCH请参阅我对以上答案的编辑。。。我认为您希望将扩展的_名称作为一个数组,然后在名称上循环。非常好,这很管用。。再次感谢您@helder sepulveda