Twitter bootstrap 3 Flask，带modal的bootstrap 3应用程序；逃生钥匙导致管道破裂

该应用程序基于flask和bootstrap 3。我有一个带有选项（data background=“static”，data keyboard=“false”）的模式，以防止用户单击或使用escape键时关闭它。单击将被忽略，但escape键会导致flask应用程序崩溃，并出现一个表示管道破裂的回溯

我相信HTML是正确的。我不知道为什么引导模式选项被忽略，为什么flask应用程序崩溃

HTML:

---

我认为这个问题与引导无关。也许你应该探索更多。但不确定：）我认为这个问题与引导无关。也许你应该探索更多。但不确定：）

<div class="modal fade" role="dialog" id="working-modal"
    data-backdrop="static" data-keyboard="false">
    <div class="modal-dialog modal-sm" role="document">
        <div class="modal-content">
            <div class="modal-body">
                <h4 class="modal-title text-center">Working</h4>
            </div>
        </div>
    </div>
</div>

File "/home/zinnia/.virtualenvs/px/local/lib/python2.7/site-packages/werkzeug/serving.py", line 499, in serve_forever
  HTTPServer.serve_forever(self)
File "/usr/lib/python2.7/SocketServer.py", line 233, in serve_forever
  self._handle_request_noblock()
File "/usr/lib/python2.7/SocketServer.py", line 292, in _handle_request_noblock
  self.handle_error(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 290, in _handle_request_noblock
  self.process_request(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 318, in process_request
  self.finish_request(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 331, in finish_request
  self.RequestHandlerClass(request, client_address, self)
File "/usr/lib/python2.7/SocketServer.py", line 654, in __init__
  self.finish()
File "/usr/lib/python2.7/SocketServer.py", line 713, in finish
  self.wfile.close()
File "/usr/lib/python2.7/socket.py", line 283, in close
  self.flush()
File "/usr/lib/python2.7/socket.py", line 307, in flush
  self._sock.sendall(view[write_offset:write_offset+buffer_size])
socket.error: [Errno 32] Broken pipe