Twitter bootstrap 如何在视图中打开引导模式onload（Yii2）

我无法通过加载相应的视图来打开引导模式。你能帮我吗

示例：当只访问地址index.php？r=client/base时，我想在屏幕上弹出一个弹出窗口

整页示例

<?php

use yii\helpers\Html;
use yii\grid\GridView;


?>
<div class="visit-index">

    <div class="row">
      <div class="col-md-6"><h1><?= Html::encode($this->title) ?></h1></div>
      <div class="col-md-6"><span class="pull-right" style="top: 15px;position: relative;"><?php  echo $this->render('/base/_menu'); ?></span></div>
    </div>
    <hr/>

    <div class="row">
      <div class="col-md-7"><?php echo $this->render('_filter', ['model' => $searchModel]); ?></div>
      <div class="col-md-5"><?= Html::a('<span class="glyphicon glyphicon-folder-close" aria-hidden="true"></span> Link para Visitas Antigas', ['/visits/visits/index'], ['class' => 'btn btn-default pull-right']) ?></div>
    </div>
    <br/>

    <div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true"></div>
    <script>
       function birthdays(){
          $.ajax({
              type:'POST',
              url:'index.php?r=/client/base/modal_birthdays',
              success: function(data)
                       {
                           $('#myModal').html(data);
                           $('#myModal').modal();
                       }
          });
       }
    </script>

    <div class="panel panel-default">
    <div class="panel-body">
    <?= GridView::widget([
        'dataProvider' => $dataProvider,
        'filterModel' => $searchModel,
        'columns' => [
            [
            'attribute' => 'id',
            'headerOptions' => ['class' => 'text-center'],
            'contentOptions'=>['style'=>'width: 3%;text-align:center'],
            ],
            'observation:ntext',
            [
            'class' => 'yii\grid\ActionColumn',
            'template' => '{view} {update} {delete}',
            'contentOptions'=>['style'=>'width: 8%;text-align:center'],
            'headerOptions' => ['class' => 'text-center'],
            ],
        ],
    ]); ?>

    </div>
    </div>
</div>

此jquery代码应将URL检测为字符串，然后设置
焦点
（打开）您的模式。如果您发布完整的html代码和所有内容，将更容易帮助您。
好的，该页面是通过GIIYou生成的标准索引（视图），您需要完整的代码。我不明白如何实现，你能在我发布的页面上发布一个完整的例子吗？
$(function() {
    if ( document.location.href.indexOf('index.php?r=/client/base/modal_birthdays') > -1 ) {
        $('#myModal').focus();
    }
});