Typescript 使用redux设置嵌套在不可变映射中的属性的值

我正在尝试使用减缩器设置

state.case.summaries.get（action.summary.id）.metadata.summaryRank

的值<代码>摘要is

Immutable.Map

我试过这个：

        return {
            ...state,
            'case' : {
                ...state.case,
                summaries : {
                    ...state.case.summaries,
                    [action.summary.id] : {
                        ...state.case.summaries.get(action.summary.id),
                        metadata : {
                            ...state.case.summaries.get(action.summary.id).metadata,
                            summaryRank : action.newRank
                        }
                    }
                }
            }
        };

但我正在失去我的类型：

`state` before:
ApplicationState {_map: Map, __ownerID: undefined}
after:
{_map: Map, __ownerID: undefined, case: {…}}


`case` before:
Case {_map: Map, __ownerID: undefined}
after:
{_map: Map, __ownerID: undefined, summaries: {…}}


`summaries` before
Map {size: 44, _root: HashArrayMapNode, __ownerID: undefined, __hash: undefined, __altered: false}
after
{size: 44, _root: HashArrayMapNode, __ownerID: undefined, __hash: undefined, __altered: false, …}

因此，如果我以后尝试执行
summaries.get（summaryId）
，我最终得到的结果是
applicationState.case.summaries.get不是一个函数


然后我试着这样做：

        return state.set('case',
            state.case.set('summaries',
                state.case.summaries.get(action.summary.id).set(//not sure what to do here
                    state.case.summaries.get(action.summary.id).set('metadata',
                        state.case.summaries.get(action.summary.id).metadata.set('summaryRank',
                            action.newRank
                        )
                    )
                )
            )
        );

但我得到了：

 [exec]
 [exec]  46                     state.case.summaries.get(action.summary.id).set(
 [exec]                         ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
 [exec]  47                         state.case.summaries.get(action.summary.id).set('metadata',
 [exec]     ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
 [exec] ...
 [exec]  51                         )
 [exec]     ~~~~~~~~~~~~~~~~~~~~~~~~~
 [exec]  52                     )
 [exec]     ~~~~~~~~~~~~~~~~~~~~~
 [exec]
 [exec] .../services/store/caseReducer.ts(46,21): error TS2346: Supplied parameters do not match any signature of call target.
 [exec]


更多信息


case.ts

const CaseRecord = Immutable.Record({
    id: '',
    reserved:false,
    loaded: false,
    summaries: Immutable.Map<string, Summary>(),
    caseMetadata: new models.CaseMetadata(),
});

export class Case extends CaseRecord {
    public id: string;
    public loaded: boolean;
    public reserved: boolean;
    public summaries: Immutable.Map<string, Summary>;
    public caseMetadata: models.CaseMetadata;

    constructor(properties?: any) {
        super(properties);
    }

    public asMutable(): Case {
        let record = <Case>super.asMutable();
        record.summaries = this.summaries.asMutable();

        this.summaries.forEach((summary) => {
            record.summaries = record.summaries.set(summary.id, <models.Summary>summary.asMutable());
        });
        record.caseMetadata = this.caseMetadata.asMutable();

        return record;
    }
}

在redux存储中使用类类型时要小心——必须确保没有使用普通的JS对象

当您执行以下操作时：

return { /* stuff */ }

return Object.assign(new ApplicationState(), { /* stuff */ })

redux无法判断您是从另一种类型派生出来的。您可以通过以下方式应用原始原型：

return { /* stuff */ }

return Object.assign(new ApplicationState(), { /* stuff */ })

然而，当有大量的筑巢时，这是相当乏味的

谢天谢地，您似乎一直在使用不可变的东西，这使得更新嵌套类型相当容易。我相信你可以做到：

return state.setIn(
    ['case', 'summaries', action.summary.id, 'metadata', 'summaryRank'],
    action.newRank
)

这将根据需要创建键，并根据需要使用Immutable的映射。
由于我没有看到ApplicationState和Case类，所以有点难以确定发生了什么。有什么理由让它们成为类，而不是一路使用Immutable.js映射吗？@KevinRaoofi-我已经在上面添加了这些类。这些类的可能重复实现了这个目的，并且比我预期的要干净得多。谢谢