Typescript:根据对象中的属性确定对象类型';s属性
我可能对Typescript要求太多,但我想知道这样的事情是否可能:Typescript:根据对象中的属性确定对象类型';s属性,typescript,discriminated-union,conditional-types,Typescript,Discriminated Union,Conditional Types,我可能对Typescript要求太多,但我想知道这样的事情是否可能: interface ObjectType { type: 'this' | 'that'; } interface SomeObject { objType: ObjectType } interface ThisObject extends SomeObject { objType: { type: 'this' } thisProp: 'anything' } interface Th
interface ObjectType {
type: 'this' | 'that';
}
interface SomeObject {
objType: ObjectType
}
interface ThisObject extends SomeObject {
objType: { type: 'this' }
thisProp: 'anything'
}
interface ThatObject extends SomeObject {
objType: { type: 'that' };
thatProp: 'something'
}
function getProp(obj: ThisObject | ThatObject) {
switch (obj.objType.type) {
case 'this':
return {
type: obj.objType.type,
prop: obj.thisProp
};
case 'that':
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
Typescript能够正确地缩小obj.objType.type
,但是我试图在返回的对象中分配给prop
的值不会进行类型检查。两者的错误相同(显然属性名称不同):
这样的事情可能吗?我也试过这样的方法:
interface SomeObject {
objType: ObjectType;
thisProp: SomeObject['objType'] extends 'this' ? 'anything' : never;
thatProp: SomeObject['objType'] extends 'that' ? 'something' : never;
}
type PickObject<T> = T extends 'this' ? ThisObject : ThatObject;
function getProp<T extends 'this' | 'that'>(obj: PickObject<T>) {
switch (obj.objType.type) {
case 'this':
return {
type: obj.objType.type,
prop: obj.thisProp
};
case 'that':
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
interface ThisObject extends SomeObject { objType: { type: 'this' }; thisProp: 'anything' }
interface ThatObject extends SomeObject { objType: { type: 'that' }; thatProp: 'something' }
function nestedDiscrim<T extends object | PropertyKey, D extends object | PropertyKey>(
val: T, discriminant: D): val is Extract<T, D>;
function nestedDiscrim(val: any, discriminant: any) {
if ((typeof val === "object") && (typeof discriminant === "object")) {
for (let k in discriminant) {
if (!(k in val)) return false;
if (!nestedDiscrim(val[k], discriminant[k])) return false;
}
return true;
}
if ((typeof val !== "object") && (typeof discriminant !== "object")) {
return val === discriminant;
}
return false;
}
function getProp(obj: ThisObject | ThatObject) {
if (nestedDiscrim(obj, { objType: { type: "this" } } as const)) {
return {
type: obj.objType.type,
prop: obj.thisProp
};
} else {
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
这导致这两种道具都是从不
,以及类似的东西:
interface SomeObject {
objType: ObjectType;
thisProp: SomeObject['objType'] extends 'this' ? 'anything' : never;
thatProp: SomeObject['objType'] extends 'that' ? 'something' : never;
}
type PickObject<T> = T extends 'this' ? ThisObject : ThatObject;
function getProp<T extends 'this' | 'that'>(obj: PickObject<T>) {
switch (obj.objType.type) {
case 'this':
return {
type: obj.objType.type,
prop: obj.thisProp
};
case 'that':
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
interface ThisObject extends SomeObject { objType: { type: 'this' }; thisProp: 'anything' }
interface ThatObject extends SomeObject { objType: { type: 'that' }; thatProp: 'something' }
function nestedDiscrim<T extends object | PropertyKey, D extends object | PropertyKey>(
val: T, discriminant: D): val is Extract<T, D>;
function nestedDiscrim(val: any, discriminant: any) {
if ((typeof val === "object") && (typeof discriminant === "object")) {
for (let k in discriminant) {
if (!(k in val)) return false;
if (!nestedDiscrim(val[k], discriminant[k])) return false;
}
return true;
}
if ((typeof val !== "object") && (typeof discriminant !== "object")) {
return val === discriminant;
}
return false;
}
function getProp(obj: ThisObject | ThatObject) {
if (nestedDiscrim(obj, { objType: { type: "this" } } as const)) {
return {
type: obj.objType.type,
prop: obj.thisProp
};
} else {
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
似乎不需要
SomeObject
接口。下面是一个可能的解决方案,消除了SomeObject
接口:
问题是
ObjectType
和objType
键objType
实际上并不定义接口的类型。以下是一个工作示例:
type ObjectType = 'this' | 'that'
interface SomeObject {
type: ObjectType
}
interface ThisObject extends SomeObject {
type: 'this'
thisProp: 'anything'
}
interface ThatObject extends SomeObject {
type: 'that'
thatProp: 'something'
}
function getProp(obj: ThisObject | ThatObject) {
switch (obj.type) {
case 'this':
return {
type: obj.type,
prop: obj.thisProp
};
case 'that':
return {
type: obj.type,
prop: obj.thatProp
};
}
}
假设您的类型实际上是这样的:
interface SomeObject {
objType: ObjectType;
thisProp: SomeObject['objType'] extends 'this' ? 'anything' : never;
thatProp: SomeObject['objType'] extends 'that' ? 'something' : never;
}
type PickObject<T> = T extends 'this' ? ThisObject : ThatObject;
function getProp<T extends 'this' | 'that'>(obj: PickObject<T>) {
switch (obj.objType.type) {
case 'this':
return {
type: obj.objType.type,
prop: obj.thisProp
};
case 'that':
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
interface ThisObject extends SomeObject { objType: { type: 'this' }; thisProp: 'anything' }
interface ThatObject extends SomeObject { objType: { type: 'that' }; thatProp: 'something' }
function nestedDiscrim<T extends object | PropertyKey, D extends object | PropertyKey>(
val: T, discriminant: D): val is Extract<T, D>;
function nestedDiscrim(val: any, discriminant: any) {
if ((typeof val === "object") && (typeof discriminant === "object")) {
for (let k in discriminant) {
if (!(k in val)) return false;
if (!nestedDiscrim(val[k], discriminant[k])) return false;
}
return true;
}
if ((typeof val !== "object") && (typeof discriminant !== "object")) {
return val === discriminant;
}
return false;
}
function getProp(obj: ThisObject | ThatObject) {
if (nestedDiscrim(obj, { objType: { type: "this" } } as const)) {
return {
type: obj.objType.type,
prop: obj.thisProp
};
} else {
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
如果type
属性实际上嵌套在objType
属性中,那么您会遇到问题字段,其中嵌套的属性在TypeScript中不受真正支持。你不能将一个受歧视的联盟作为另一个受歧视联盟的歧视者;判别式必须是诸如“this”|“that”
之类的单例类型的并集
您不必等待microsoft/TypeScript#18758被寻址,您可以编写自己的代码,通过传递判别对象并使用来表示所需的缩小,其行为类似于嵌套的判别联合判别器。大概是这样的:
interface SomeObject {
objType: ObjectType;
thisProp: SomeObject['objType'] extends 'this' ? 'anything' : never;
thatProp: SomeObject['objType'] extends 'that' ? 'something' : never;
}
type PickObject<T> = T extends 'this' ? ThisObject : ThatObject;
function getProp<T extends 'this' | 'that'>(obj: PickObject<T>) {
switch (obj.objType.type) {
case 'this':
return {
type: obj.objType.type,
prop: obj.thisProp
};
case 'that':
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
interface ThisObject extends SomeObject { objType: { type: 'this' }; thisProp: 'anything' }
interface ThatObject extends SomeObject { objType: { type: 'that' }; thatProp: 'something' }
function nestedDiscrim<T extends object | PropertyKey, D extends object | PropertyKey>(
val: T, discriminant: D): val is Extract<T, D>;
function nestedDiscrim(val: any, discriminant: any) {
if ((typeof val === "object") && (typeof discriminant === "object")) {
for (let k in discriminant) {
if (!(k in val)) return false;
if (!nestedDiscrim(val[k], discriminant[k])) return false;
}
return true;
}
if ((typeof val !== "object") && (typeof discriminant !== "object")) {
return val === discriminant;
}
return false;
}
function getProp(obj: ThisObject | ThatObject) {
if (nestedDiscrim(obj, { objType: { type: "this" } } as const)) {
return {
type: obj.objType.type,
prop: obj.thisProp
};
} else {
return {
type: obj.objType.type,
prop: obj.thatProp
};
}
}
您可以看到它是有效的:
console.log(getProp({ objType: { type: "this" }, thisProp: "anything" })); // {type: "this", prop: "anything"};
console.log(getProp({ objType: { type: "that" }, thatProp: "something" })); // {type: "that", prop: "something"};
其思想是,
nestedDiscrim(obj,{objType:{type:{type:{this“}}})
遍历obj
,查看obj.objType.type
,并将其与“this”
进行比较。如果它们是相同的,那么我们将obj
从ThisObject | ThatObject
缩小为ThisObject
。否则,我们将obj
从ThisObject | ThatObject
缩小为ThatObject
好吧,希望这会有帮助;祝你好运
您能修复您的接口吗?大概您需要类似于
接口ThisObject扩展SomeObject{objType:{type:'this'};thisProp:'anythis'}
和接口ThatObject扩展SomeObject{objType:{type:'that'};thatProp:'somethis'}
。不幸的是,这并不能神奇地发挥作用,但至少你的类型会与你实际做的相符。