Typescript 猜测选择函数的返回类型

我希望TypeScript能够猜出out的类型，这是一个字符串-我该怎么做？

您可以为makeSelector分配泛型类型参数，使TypeScript能够推断返回函数的返回类型：

常量stateObj={ 财产：{ 嵌套：someString } }; const-makeSelector=selectingFunction:state:StateType=>ReturnType=>state:StateType=>selectingFunctionstate； // −−−−−−−−−−−−−−−−−−^^^^^^^^^^^^^^^^^^^^^^^−−−−−−−−−−−−−−−−−−^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^−−−−−^−−−−−^^^^^^^^^^^^ const selector=makeSelectorstate:typeof stateObj=>state.property.nested； const out=选择器状态对象；

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您可以将泛型类型参数分配给makeSelector，使TypeScript能够推断返回函数的返回类型：

常量stateObj={ 财产：{ 嵌套：someString } }; const-makeSelector=selectingFunction:state:StateType=>ReturnType=>state:StateType=>selectingFunctionstate； // −−−−−−−−−−−−−−−−−−^^^^^^^^^^^^^^^^^^^^^^^−−−−−−−−−−−−−−−−−−^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^−−−−−^−−−−−^^^^^^^^^^^^ const selector=makeSelectorstate:typeof stateObj=>state.property.nested； const out=选择器状态对象；

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旁注：这个术语是推断而不是猜测。仅用于搜索目的。：-特点是类型推断。旁注：这个术语是推断而不是猜测。仅用于搜索目的。：-其特点是类型推断。

const stateObj = {
  property: {
    nested: "someString"
  }
}

const makeSelector = (selectingFunction) => state => selectingFunction(state); // may include some addiitonal logic, such as memoization

const selector = makeSelector((state: typeof stateObj) => state.property.nested);

const out = selector(stateObj); // How do I make TypeScript guess its type?