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Typescript 如何将泛型类型传递给来自类的泛型方法？

typescript

Typescript 如何将泛型类型传递给来自类的泛型方法？,typescript,typescript-generics,Typescript,Typescript Generics,假设我有一个类，我想要一个foo的别名类型 class A { foo<T>() {} } // How to I pass "T"? TS could not parse "A['foo']<T>" or " <T>A['foo']" type FooType<T> = A['foo'] A类{ foo（）{} } //如何通过“T”？TS无法分析“A['foo']”或“A['

假设我有一个类，我想要一个foo的别名类型

class A {
  foo<T>() {}
}

// How to I pass "T"? TS could not parse  "A['foo']<T>" or " <T>A['foo']"
type FooType<T> = A['foo']

A类{
foo（）{}
}
//如何通过“T”？TS无法分析“A['foo']”或“A['foo']”
类型FooType=A['foo']
试试这个：

function foo<Type>(arg: Type): Type {}

函数foo（arg:Type）：类型{
致电：

foo<string>();

foo（）；