Unit testing 如何设置后台状态代码？

对于HTTP测试，我有以下提供程序

  providers: [
    MockBackend,
    BaseRequestOptions,
    {
      provide: Http,
      useFactory: (pBackend: MockBackend, pOptions: BaseRequestOptions) => {
        return new Http(pBackend, pOptions);
      },
      deps: [MockBackend, BaseRequestOptions]
    }
  ]

我可以嘲笑成功的回应

let backend = injector.get(MockBackend);
backend.connections.subscribe(
  (connection: MockConnection) => {
    connection.mockRespond(new Response(
      new ResponseOptions({
          body: {mydata:'somedata'}
        }
      )));
  });

let backend = injector.get(MockBackend);
backend.connections.subscribe(
  (connection: MockConnection) => {
    connection.mockError(new Error('error'));
  });

和一个错误响应

let backend = injector.get(MockBackend);
backend.connections.subscribe(
  (connection: MockConnection) => {
    connection.mockRespond(new Response(
      new ResponseOptions({
          body: {mydata:'somedata'}
        }
      )));
  });

let backend = injector.get(MockBackend);
backend.connections.subscribe(
  (connection: MockConnection) => {
    connection.mockError(new Error('error'));
  });

但是，请问，我如何嘲笑非200回答。例如，我如何响应HTTP状态代码418

---

谢谢

只需在

响应选项中添加一个status属性

new ResponseOptions({
  body: {mydata:'somedata'},
  status: 418
})

---

有关其他属性的信息，请参见

，请注意-这不会触发

catch

函数，也不会触发

.subscribe

上的第二个函数，如果这是他在单元测试中尝试测试的