Web scraping 如何使用python web scraping提取每个产品的标题

以下是链接：

---

查找所有

div

，其中包含

class

name

name

（class=“name”）。这会给你所有的书名。如果您想要

href

，请遍历所有

标题

，并找到

一个
标签，该标签具有
标题
是
标题的文本。文本

import requests
import bs4 as bs

url = 'https://www.118100.se/sok/foretag/?q=brf&loc=&ob=rel&p=0'

response = requests.get(url)
# print('Response:', response.status_code)

soup = bs.BeautifulSoup(response.text, 'lxml')
titles = soup.find_all('div',  {'class': 'Name'})

# a = soup.find_all('a')
# print(a)

for title in titles:
    link = soup.find('a',  {'title': title.text}).get('href')
    print('https://www.118100.se' + link)

您好，谢谢，但此代码仅显示“response 200”。您能修改它，使它只显示标题链接吗？求你了，先生@卡迪亚先生
import requests
import bs4 as bs

url = 'https://www.118100.se/sok/foretag/?q=brf&loc=&ob=rel&p=0'

response = requests.get(url)
# print('Response:', response.status_code)

soup = bs.BeautifulSoup(response.text, 'lxml')
titles = soup.find_all('div',  {'class': 'Name'})

# a = soup.find_all('a')
# print(a)

for title in titles:
    link = soup.find('a',  {'title': title.text}).get('href')
    print('https://www.118100.se' + link)