Xcode 找不到类型为';字符串';接受类型为';(格式:字符串,参数:UInt32)
我在Xcode 6.3(6D570)中创建了一个游乐场,并输入以下代码:Xcode 找不到类型为';字符串';接受类型为';(格式:字符串,参数:UInt32),xcode,swift,syntax-error,Xcode,Swift,Syntax Error,我在Xcode 6.3(6D570)中创建了一个游乐场,并输入以下代码: import UIKit var randum_num = arc4random_uniform(13) + 1 String(format: "card%i", arguments: randum_num) 我得到了这个错误: cannot find an initializer for type 'String' that accepts an argument list of type '(format: Stri
import UIKit
var randum_num = arc4random_uniform(13) + 1
String(format: "card%i", arguments: randum_num)
我得到了这个错误:
cannot find an initializer for type 'String' that accepts an argument list of type '(format: String, argument: UInt32
对不起,我是全新的Swift,谢谢你的建议
另外,我正在学习本教程:您只需省略“参数:”。尝试如下:
let randum_num = arc4random_uniform(13) + 1
String(format: "card%i", randum_num)
或者干脆
String(format: "card%i", arc4random_uniform(13) + 1)