Xml 使用XPath查找连续同级
对于XPath专家来说,这里有一个简单的要点!:) 文件结构:Xml 使用XPath查找连续同级,xml,xpath,nokogiri,Xml,Xpath,Nokogiri,对于XPath专家来说,这里有一个简单的要点!:) 文件结构: <tokens> <token> <word>Newt</word><entityType>PROPER_NOUN</entityType> </token> <token> <word>Gingrich</word><entityType>PROPER_NOUN</e
<tokens>
<token>
<word>Newt</word><entityType>PROPER_NOUN</entityType>
</token>
<token>
<word>Gingrich</word><entityType>PROPER_NOUN</entityType>
</token>
<token>
<word>admires</word><entityType>VERB</entityType>
</token>
<token>
<word>Garry</word><entityType>PROPER_NOUN</entityType>
</token>
<token>
<word>Trudeau</word><entityType>PROPER_NOUN</entityType>
</token>
</tokens>
。。。它可以找到两个连续的专有名词标记中的第二个,但我不知道如何让它发出第一个标记
一些注意事项:
- 我不介意对节点集进行更高级别的处理(例如在Ruby/Nokogiri中),如果这样可以简化问题的话
- 如果有三个或更多连续的专有名词标记(称它们为A、B、C),理想情况下我希望发出[A、B]、[B、C]
def extract(doc)
names = []
sentences = doc.xpath("//tokens")
sentences.each do |sentence|
tokens = sentence.xpath("token")
prev = nil
tokens.each do |token|
name = token.xpath("word").text if token.xpath("entityType").text == "PROPER_NOUN"
names << [prev, name] if (name && prev)
prev = name
end
end
names
end
def提取(doc)
名称=[]
语句=doc.xpath(//标记)
每句话
tokens=句子.xpath(“token”)
上一个=零
代币。每个do |代币|
name=token.xpath(“word”).text if-token.xpath(“entityType”).text==“专有名词”
name我将分两步完成这项工作。第一步是选择一组节点:
//token[entityType='PROPER_NOUN' and following-sibling::token[1][entityType='PROPER_NOUN']]
这将为您提供启动2字对的所有标记。然后,为了获得实际的对,在节点列表上迭代并提取/word
和以下兄弟::令牌[1]/word
使用XmlStarlet(用于快速xml操作的工具)命令行
xml sel -t -m "//token[entityType='PROPER_NOUN' and following-sibling::token[1][entityType='PROPER_NOUN']]" -v word -o "," -v "following-sibling::token[1]/word" -n /tmp/tok.xml
给予
Newt,Gingrich
Garry,Trudeau
XmlStarlet还将把该命令行编译为xslt,相关位为
<xsl:for-each select="//token[entityType='PROPER_NOUN' and following-sibling::token[1][entityType='PROPER_NOUN']]">
<xsl:value-of select="word"/>
<xsl:value-of select="','"/>
<xsl:value-of select="following-sibling::token[1]/word"/>
<xsl:value-of select="' '"/>
</xsl:for-each>
使用Nokogiri,它可能看起来像:
#解析文档
doc=Nokogiri::XML(文档字符串)
#选择启动2字对的所有标记
pair\u start=doc.xpath'//token[entityType=“property\u noon”和以下同级::token[1][entityType=“property\u noon”]'
#提取每个单词和下面的单词
结果=配对开始。每个带有_对象([])的|节点、数组|
数组XPath返回节点或节点集,但不返回组。所以你必须确定每个小组的开始,然后抓住剩下的
first = "//token[entityType='PROPER_NOUN' and following-sibling::token[1][entityType='PROPER_NOUN']]/word"
next = "../following-sibling::token[1]/word"
doc.xpath(first).map{|word| [word.text, word.xpath(next).text] }
输出:
[["Newt", "Gingrich"], ["Garry", "Trudeau"]]
此XPath 1.0表达式:
/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
==============
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
</xsl:template>
</xsl:stylesheet>
<word>Newt</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Trudeau</word>
<word>Newt</word>
<word>Gingrich</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Rep</word>
<word>Trudeau</word>
选择所有“成对第一名词词”
此XPath表达式:
/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
==============
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
</xsl:template>
</xsl:stylesheet>
<word>Newt</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Trudeau</word>
<word>Newt</word>
<word>Gingrich</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Rep</word>
<word>Trudeau</word>
选择所有“第二对名词词”
您必须以生成的两个结果节点集的第k个节点生成实际对
基于XSLT的验证:
/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
==============
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
</xsl:template>
</xsl:stylesheet>
<word>Newt</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Trudeau</word>
<word>Newt</word>
<word>Gingrich</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Rep</word>
<word>Trudeau</word>
及
当对该XML文档应用相同的转换时(注意,我们现在有三个示例):
及
注意事项:
/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
following-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
==============
<xsl:copy-of select=
"/*/token
[entityType='PROPER_NOUN'
and
preceding-sibling::token[1]/entityType = 'PROPER_NOUN'
]
/word
"/>
</xsl:template>
</xsl:stylesheet>
<word>Newt</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Trudeau</word>
<word>Newt</word>
<word>Gingrich</word>
<word>Garry</word>
==============
<word>Gingrich</word>
<word>Rep</word>
<word>Trudeau</word>
可以使用单个XPath 2.0表达式生成所需的结果。如果您对XPath 2.0解决方案感兴趣,请务必告诉我。仅XPath一项功能不足以完成此任务。但是XSLT非常简单:
<xsl:for-each-group select="token" group-adjacent="entityType">
<xsl:if test="current-grouping-key="PROPER_NOUN">
<xsl:copy-of select="current-group">
<xsl:text>====</xsl:text>
<xsl:if>
</xsl:for-each-group>
我得出的答案与您的答案几乎相同,因此我在这个答案中添加了一个使用Nokogiri的示例,而不是添加另一个答案。