Warning: file_get_contents(/data/phpspider/zhask/data//catemap/0/xml/14.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
XSLT从xml调用属性值_Xml_Xslt - Fatal编程技术网

XSLT从xml调用属性值

XSLT从xml调用属性值,xml,xslt,Xml,Xslt,我有这个xml,我正试图使用xslt显示它。我可以显示日期和球队名称,但无法获得要显示的分数值 <teamscores> <season year="2015"> <game> <date>20151004</date> <team1 score="77">MIA</team1> <team2 score="

我有这个xml,我正试图使用xslt显示它。我可以显示日期和球队名称,但无法获得要显示的分数值

<teamscores>
    <season year="2015">
        <game>  
            <date>20151004</date>
            <team1 score="77">MIA</team1>
            <team2 score="90">CHA</team2>
        </game>

20151004
米娅
恰恰


日期:

假设此时的上下文是
,正确的XPath表达式是
team1/@score
,即

(<xsl:value-of select ="team1/@score"/>)
()

假设该点的上下文是
,正确的XPath表达式是
team1/@score
,即

(<xsl:value-of select ="team1/@score"/>)
()