通过使用XPath从WSDL文件中导入的(“xsd:import”)模式获取XML元素声明
我有个问题已经困扰了我一周了 我使用Netbeans 7.2.1将虚拟web服务编程为无状态EJB:通过使用XPath从WSDL文件中导入的(“xsd:import”)模式获取XML元素声明,xml,xpath,wsdl,xsd,Xml,Xpath,Wsdl,Xsd,我有个问题已经困扰了我一周了 我使用Netbeans 7.2.1将虚拟web服务编程为无状态EJB: @WebService(serviceName = "WSPersonLookup") @Stateless() public class WSPersonData { @PersistenceContext(unitName="PUWSPersonData") private EntityManager em; /** * Web service operation */
@WebService(serviceName = "WSPersonLookup")
@Stateless()
public class WSPersonData {
@PersistenceContext(unitName="PUWSPersonData")
private EntityManager em;
/**
* Web service operation
*/
@WebMethod(operationName = "getPersonData")
public Person getPersonData(@WebParam(name = "personId") final String personId) {
return em.find(Person.class, personId);
}
}
类“Person”只是映射到此表的JPA实体(我使用PostgreSQL作为DBMS):
产生的WSDL如下所示:
<?xml version="1.0" encoding="UTF-8"?>
<definitions xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" xmlns:wsp="http://www.w3.org/ns/ws-policy" xmlns:wsp1_2="http://schemas.xmlsoap.org/ws/2004/09/policy" xmlns:wsam="http://www.w3.org/2007/05/addressing/metadata" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:tns="http://ws.i2b.com/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://schemas.xmlsoap.org/wsdl/" targetNamespace="http://ws.i2b.com/" name="WSPersonLookup">
<types>
<xsd:schema>
<xsd:import namespace="http://ws.i2b.com/" schemaLocation="http://pc-i2b:8080/WSPersonLookup/WSPersonData?xsd=1" />
</xsd:schema>
</types>
<message name="getPersonData">
<part name="parameters" element="tns:getPersonData" />
</message>
<message name="getPersonDataResponse">
<part name="parameters" element="tns:getPersonDataResponse" />
</message>
<portType name="WSPersonData">
<operation name="getPersonData">
<input wsam:Action="http://ws.i2b.com/WSPersonData/getPersonDataRequest" message="tns:getPersonData" />
<output wsam:Action="http://ws.i2b.com/WSPersonData/getPersonDataResponse" message="tns:getPersonDataResponse" />
</operation>
</portType>
<binding name="WSPersonDataPortBinding" type="tns:WSPersonData">
<soap:binding transport="http://schemas.xmlsoap.org/soap/http" style="document" />
<operation name="getPersonData">
<soap:operation soapAction="" />
<input>
<soap:body use="literal" />
</input>
<output>
<soap:body use="literal" />
</output>
</operation>
</binding>
<service name="WSPersonLookup">
<port name="WSPersonDataPort" binding="tns:WSPersonDataPortBinding">
<soap:address location="http://pc-i2b:8080/WSPersonLookup/WSPersonData" />
</port>
</service>
</definitions>
XSD声明:
<?xml version='1.0' encoding='UTF-8'?>
<xs:schema xmlns:tns="http://ws.i2b.com/" xmlns:xs="http://www.w3.org/2001/XMLSchema"
version="1.0" targetNamespace="http://ws.i2b.com/">
<xs:element name="getPersonData" type="tns:getPersonData"/>
<xs:element name="getPersonDataResponse" type="tns:getPersonDataResponse"/>
<xs:element name="person" type="tns:person"/>
<xs:complexType name="getPersonData">
<xs:sequence>
<xs:element name="personId" type="xs:string" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="getPersonDataResponse">
<xs:sequence>
<xs:element name="return" type="tns:person" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="person">
<xs:sequence>
<xs:element name="address" type="xs:string" minOccurs="0"/>
<xs:element name="creationDate" type="xs:dateTime" minOccurs="0"/>
<xs:element name="id" type="xs:string" minOccurs="0"/>
<xs:element name="name" type="xs:string" minOccurs="0"/>
<xs:element name="nit" type="xs:string" minOccurs="0"/>
<xs:element name="phone" type="xs:int"/>
</xs:sequence>
</xs:complexType>
</xs:schema>
问题是:我需要访问上面在WSDL中导入的模式声明:
<types>
<xsd:schema>
<xsd:import namespace="http://ws.i2b.com/" schemaLocation="http://pc-i2b:8080/WSPersonLookup/WSPersonData?xsd=1" />
</xsd:schema>
</types>
通过使用XPath。我不允许直接访问模式
有办法吗?如果没有,有人知道这方面的解决方法吗
问候。您不能仅使用XPath获取主XML文档(WSDL)引用的辅助XML文档(本例中的模式) 使用XSLT,您可以使用
document()
函数:
<xsl:variable name="schema" select="document(/soap:definitions/soap:types/xsd:schema/xsd:import/@schemaLocation)"/>
或者,与其尝试获取导入的模式,不如使用类似于/soap:definitions/soap:types/xsd:schema
的XPath获取WSDL中的模式片段。这是一个有效的架构,正在导入http://pc-i2b:8080/WSPersonLookup/WSPersonData?xsd=1
-您应该能够直接使用它
<xsl:variable name="schema" select="document(/soap:definitions/soap:types/xsd:schema/xsd:import/@schemaLocation)"/>