Xml xquery fn:current-date（）格式

我在上面尝试过，但是

fn:current-date（）

将日期输出为

2014-03-30Z

---

但是，如果dueDate高于当前日期，我需要将dueDate与当前日期进行比较，然后显示所有用户。

由于这显然是一个练习，我将不提供完整答案，而是提供解决方案的草图

XML文档中使用的日期格式很难比较。创建一个执行以下步骤的函数可能是合理的（但当然也可以不执行这些步骤）：

• 您必须

  标记（…）

  它，将月份解析为数字，并将其连接为

  YYYY-mm-dd

• 现在可以使用

  xs:date（$string）

  将其转换为日期对象

现在循环所有

元素，并在那里

where

子句中过滤它们，调用您编写的函数或将代码放在这里

作为最后一步，您必须将

对象解析给相应的用户

这将有助于您编写代码。如果您有任何进一步的具体问题或遇到问题，请随时发布后续问题（包括您尝试过的问题）

---

更新：这是我的代码，使用的索引查找月份。

resolveDate

函数在代码中被注释，剩下的查询很简单

for $x in doc("library.xml")/library
where  $x/@dueDate > fn:current-date()
return $x/@name

将函数local:resolveDate（$date作为xs:string）声明为xs:date{
（：月索引，以便我们可以查找：）
let$months:=（“一月”、“二月”、“三月”、“四月”、“五月”、“六月”、“七月”、“八月”、“九月”、“十月”、“十一月”、“十二月”）
（：拆分日期：）
让$date:=标记化（$date，'-'））
（：将月份解析为其两位数：）
让$month:=将（$months，$date[2]）的索引转换为xs:string
设$month:=if（字符串长度（$month）<2）
然后concat（'0'，$month）
每月其他$
（：从重新排序的日期构造xs:date对象：）
让$date:=字符串联接（$date[3]，$month，$date[1]），“-”）
返回xs:date（$date）
};
对于//user中的$user
对于//loan[@user=$user/id/@val]中的$loan
其中本地：resolveDate（$loan/@dueDate）<当前日期（）
返回$user

您可以创建如下函数：

declare function local:resolveDate($date as xs:string) as xs:date {
  (: Month index, so we can look it up :)
  let $months := ("Jan", "Feb", "March", "April", "May", "June", "July", "Aug", "Sep", "Oct", "Nov", "Dec")
  (: Split up the date :)
  let $date := tokenize($date, '-')
  (: Resolve the month to its two digit number :)
  let $month := index-of($months, $date[2]) cast as xs:string
  let $month := if (string-length($month) < 2)
                then concat('0', $month)
                else $month
  (: Construct an xs:date object from the reordered date :)
  let $date := string-join(($date[3], $month , $date[1]), '-')
  return xs:date($date)
};

for $user in //user
for $loan in //loan[@user=$user/id/@val]
where local:resolveDate($loan/@dueDate) < current-date()
return $user

---

它应该适合您。

该函数称为

tokenize

，而不是

tokenise

。另外，我会使用标记化破折号，而不是空格：

tokenize（“2010年4月25日），“-”）

。我正在尝试使用标记化（）将dueDate分解为数字，但会出现错误。请阅读如何发布破折号，以便有人能够真正回答您的问题。由于您的问题是一个新的、独立的问题，最好是实际发布一个，而不是发表评论。您可以这样做，与我在展示自己的努力后添加的代码版本进行比较。再看一看我在回答中描述的解决方案草图。不能直接将XML中提供的日期与当前日期进行比较。

declare function local:resolveDate($date as xs:string) as xs:date {
  (: Month index, so we can look it up :)
  let $months := ("Jan", "Feb", "March", "April", "May", "June", "July", "Aug", "Sep", "Oct", "Nov", "Dec")
  (: Split up the date :)
  let $date := tokenize($date, '-')
  (: Resolve the month to its two digit number :)
  let $month := index-of($months, $date[2]) cast as xs:string
  let $month := if (string-length($month) < 2)
                then concat('0', $month)
                else $month
  (: Construct an xs:date object from the reordered date :)
  let $date := string-join(($date[3], $month , $date[1]), '-')
  return xs:date($date)
};

for $user in //user
for $loan in //loan[@user=$user/id/@val]
where local:resolveDate($loan/@dueDate) < current-date()
return $user

declare function local:xml_month

($monthId as xs:string) as xs:string
{
if (tokenize($monthId,"-")[2] = 'January')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'January','01'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'February')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'February','02'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'March')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'March','03'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'April')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'April','04'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'May')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'May','05'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'June')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'June','06'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'July')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'July','07'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'August')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'August','08'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'September')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'Sempter','09'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'October')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'October','10'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'November')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'November','11'),"-",
tokenize($monthId,"-")[3])
else if (tokenize($monthId,"-")[2] = 'December')
then  
concat(  tokenize($monthId,"-")[1],"-",
replace(tokenize($monthId,"-")[2],'December','12'),"-",
tokenize($monthId,"-")[3])    
else "NA"
};

for $u in doc("ques2010.xml")//user
for $l in doc("ques2010.xml")//loan    
where fn:current-date() > xs:date(local:xml_month($l/data(@dueDate)))
and $u/id/@val = $l/@user
return $u/name