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Xslt XSL 1.0的问题<;xsl:for each>;及<;呼叫模板>;_Xslt - Fatal编程技术网

Xslt XSL 1.0的问题<;xsl:for each>;及<;呼叫模板>;

Xslt XSL 1.0的问题<;xsl:for each>;及<;呼叫模板>;,xslt,Xslt,请查看我的代码,并就此向我提供建议: XML文件:content.XML: <content> <page id="page-1"> <!-- ... --> <block-center> <block-center-row id="block-center-row-1"> <cd> <title>Empire Burlesque</title> <artis

请查看我的代码,并就此向我提供建议:

XML文件:
content.XML

<content>
<page id="page-1">
<!-- ... -->
<block-center>
  <block-center-row id="block-center-row-1">
    <cd>
      <title>Empire Burlesque</title>
      <artist>Bob Dylan</artist>
      <country>USA</country>
      <company>Columbia</company>
      <price>10.90</price>
      <year>1985</year>
    </cd>
    <cd>
      <title>Hide your heart</title>
      <artist>Bonnie Tyler</artist>
      <country>UK</country>
      <company>CBS Records</company>
      <price>9.90</price>
      <year>1988</year>
    </cd>
  </block-center-row>
  <block-center-row id="block-center-row-2">
    <block-center-colunm id="block-center-2-1">
      <book>
        <title>Book Title1</title>
        <author>Book Author1</author>
      </book>
      <book>
        <title>Book Title2</title>
        <author>Book Author2</author>
      </book>
      <book>
        <title>Book Title3</title>
        <author>Book Author3</author>
      </book>
    </block-center-colunm>
    <block-center-colunm id="block-center-2-2">
      <seminar>
        <author>Seminar author1</author>
        <durable>3</durable>
      </seminar>
      <seminar>
        <author>Seminar author2</author>
        <durable>1.5</durable>
      </seminar>
      <seminar>
        <author>Seminar author3</author>
        <durable>2</durable>
      </seminar>
      <seminar>
        <author>Seminar author4</author>
        <durable>3</durable>
      </seminar>
    </block-center-colunm>
  </block-center-row>
</block-center>
</page>
<!-- ... -->
</content>
XSL文件
块中心.XSL

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template name="block-center-row-1">
    <div class="block-center-row">
      <h2>My CD Collection</h2>
      <table border="1" width="100%">
        <tr bgcolor="#9acd32">
          <th>Title</th>
          <th>Artist</th>
        </tr>
        <xsl:for-each select="
          content/page[@id=$pageId]/block-center/
          block-center-row[@id='block-center-row-1']/cd
        ">
          <tr>
            <td>
              <xsl:value-of select="title" />
            </td>
            <xsl:choose>
              <xsl:when test="price &gt; 10">
                <td bgcolor="#ff00ff">
                  <xsl:value-of select="artist" />
                </td>
              </xsl:when>
              <xsl:when test="price &gt; 9">
                <td bgcolor="#cccccc">
                  <xsl:value-of select="artist" />
                </td>
              </xsl:when>
              <xsl:otherwise>
                <td>
                  <xsl:value-of select="artist" />
                </td>
              </xsl:otherwise>
            </xsl:choose>
          </tr>
        </xsl:for-each>
      </table>
    </div>
  </xsl:template>
</xsl:stylesheet>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:import href="block-center-1-1.xsl" />
  <xsl:template name="block-center">
    <!-- if put here. It work properly -->
    <div class="block-center"> 
      <xsl:for-each select="content/page[@id=$pageId]/block-center/block-center-row">
        <xsl:choose>
          <!-- // I does not work here --> 
          <xsl:when test="@id='block-center-row-1'">
            <xsl:call-template name="block-center-row-1" />
          </xsl:when>
        </xsl:choose>
      </xsl:for-each>
    </div>
  </xsl:template>
</xsl:stylesheet>


如果我调用
内部
循环,我不知道为什么它不工作(不输出数据)。否则没关系。

我有几句话要说。首先,在XML中产生格式含义是个坏主意。将元素称为
不仅是不必要的冗长,而且当它们的内容不再显示在中间的块中时,还会让你头疼

其次,放开
。如果您有过程编程背景,它们可能看起来很方便,但它们是错误的选择。使用
相反,它会生成更干净、更容易理解的代码

现在转到XSL。您的第二个XSL(
block center.XSL
)-它做什么?为什么有两个单独的XSL文件?此外,它缺少变量或参数声明。我用过:

<xsl:variable name="pageId" select="'page-1'" />
因此,在for each循环中,您只需执行以下操作:

<xsl:for-each select="cd">


它将开始输出所有
节点。

非常感谢您的euthusiasm! 如果我在block-center-1-1.xsl文件中进行更改,它现在可以正常工作 到


或者

根据您给我们的信息,这永远不会起作用-根本没有匹配的模板。你需要提供更完整的代码。奇怪。。。右下角写着“6次修订”,但实际上只有3次修订。
content/page[@id=$pageId]/block-center/block-center-row
<xsl:for-each select="cd">