YouTube liveStreaming API方法LiveStream.list不';YouTube提出的t返回流
我偶然发现了一个意想不到的行为 每当我请求YouTube liveStreaming API方法LiveStream.list不';YouTube提出的t返回流,youtube,youtube-api,youtube-data-api,Youtube,Youtube Api,Youtube Data Api,我偶然发现了一个意想不到的行为 每当我请求liveStream.list方法时,我得到的唯一流就是由编码软件或liveStream.insert调用启动的流 我想取而代之的是YouTube在 默认编码器设置: 我做错什么了吗?您可以通过在中传递broadcastType参数的persistent来检索有关默认广播或“现在流”广播的信息。这是我的最终完整代码,$api\u Stream\u url包含ServerURL/StreamKey 持续–仅返回持续广播 cdn-格式,rtmp,strea
liveStream.list
方法时,我得到的唯一流就是由编码软件或liveStream.insert
调用启动的流
我想取而代之的是YouTube在
默认编码器设置:
我做错什么了吗?您可以通过在中传递broadcastType参数的persistent来检索有关默认广播或“现在流”广播的信息。这是我的最终完整代码,
$api\u Stream\u url
包含ServerURL/StreamKey
持续–仅返回持续广播
cdn-格式
,rtmp
,streamName
,摄取地址
try {
// Execute an API request that lists broadcasts owned by the user who
// authorized the request.
$broadcastsResponse = $youtube->liveBroadcasts->listLiveBroadcasts(
'id,snippet,contentDetails',
array(
'broadcastType' => 'persistent',
'mine' => 'true',
));
$boundStreamId = $broadcastsResponse['items']['0']['contentDetails']['boundStreamId'];
$streamsResponse = $youtube->liveStreams->listLiveStreams('id,snippet,cdn', array(
// 'mine' => 'true',
'id' => $boundStreamId
));
/**
*
* (
[format] => 720p
[ingestionType] => rtmp
[ingestionInfo] => Array
(
[streamName] => 4vem-9233-mz3y-detq
[ingestionAddress] => rtmp://a.rtmp.youtube.com/live2
[backupIngestionAddress] => rtmp://b.rtmp.youtube.com/live2?backup=1
)
[resolution] => 720p
[frameRate] => 30fps
)
*/
$ingestionInfo = $streamsResponse['items']['0']['cdn']['ingestionInfo'];
/**
* (
[publishedAt] => 2016-06-08T12:58:38.000Z
[channelId] => UCcdDtElpr9XM5MA1stpK
[title] => Default Stream
[description] =>
[isDefaultStream] => 1
)
*/
$broadcastsResponse = $streamsResponse['items']['0']['snippet'];
$api_stream_key = $ingestionInfo->streamName;
$api_stream_address = $ingestionInfo->ingestionAddress;
/**
* Example:
* rtmp://a.rtmp.youtube.com/live2/4vem-9233-mz3y-detq
*/
$api_stream_url = $api_stream_address."/".$api_stream_key;
return false;
} catch (Google_Service_Exception $e) {
$htmlBody = sprintf('<p>A service error occurred: <code>%s</code></p>',
htmlspecialchars($e->getMessage()));
} catch (Google_Exception $e) {
$htmlBody = sprintf('<p>An client error occurred: <code>%s</code></p>',
htmlspecialchars($e->getMessage()));
}
看来这是不可能的。通读这篇文章,还没有办法做到这一点。但是,您可以尝试手动设置liveBroadcast和liveStream对象,将它们与liveBroadcasts绑定。绑定、测试流,并使用status在liveStream对象上转换为live。StreamStatus a
broadcast
(aka event)必须具有流
(尽管数据可能稍后会出现),问题是你在一个广播
页面上,所以YouTube自动生成流
。