Zend framework 如何在Zend框架中定义关系
我有两个简单的表:Zend framework 如何在Zend框架中定义关系,zend-framework,zend-db,zend-db-table,Zend Framework,Zend Db,Zend Db Table,我有两个简单的表:Projects和SubProjects,我想将每个子项目和各自的项目打印在一个表中 所以我写了这个: class Admin_Model_Projects extends Zend_Db_Table_Abstract { protected $_name = 'main_projects'; protected $_primary = 'mai_id'; protected $_sequence = true; protected $_depe
Projects
和SubProjects
,我想将每个子项目和各自的项目打印在一个表中
所以我写了这个:
class Admin_Model_Projects extends Zend_Db_Table_Abstract
{
protected $_name = 'main_projects';
protected $_primary = 'mai_id';
protected $_sequence = true;
protected $_dependentTables = array('Admin_Model_SubProjects');
....
这是:
class Admin_Model_SubProjects extends Zend_Db_Table_Abstract
{
protected $_name = 'sub_projects';
protected $_primary = 'sub_id';
protected $_sequence = true;
protected $_referenceMap = array(
'columns' => 'mai_id',
'refTableClass' => 'Admin_Model_Projects',
'refColumns' => 'mai_id'
);
.....
我想知道为什么当我键入
时,我没有从表管理\u Model\u子项目中得到对表管理\u Model\u项目的引用,你应该在所有相关的表类中定义$\u referenceMap
和$\u dependentTables
。完成后,它看起来将接近镜像。看起来您在引用映射定义中缺少规则名称。
应该是
protected $_referenceMap = array(
'Project' => array(
'columns' => 'mai_id',
'refTableClass' => 'Admin_Model_Projects',
'refColumns' => 'mai_id'
)
);