.net RabbitMQ点网客户端'；s EventingBasicConsumer.Received不能同时触发多次？

我使用RabbitMQ.Client（我从NuGet获得）访问RabbitMQ。这是我的信息消费者代码：

        const string EXCHANGE_NAME = "EXCHANGE3";
        ConnectionFactory factory = new ConnectionFactory();
        using (IConnection connection = factory.CreateConnection()) {
            using (IModel channel = connection.CreateModel()) {
                channel.ExchangeDeclare(EXCHANGE_NAME, ExchangeType.Topic, false, true, null);
                string queueName = channel.QueueDeclare();
                channel.BasicQos(0, 4, false); //I want to handle 4 messages simultaneously
                EventingBasicConsumer consumer = new EventingBasicConsumer(channel);
                consumer.Received += (o, e) => {
                    string data = Encoding.ASCII.GetString(e.Body);
                    Console.WriteLine("received: " + data);
                    Thread.Sleep(1000);
                    Console.WriteLine("done."); //Received event will not be fired again before done.
                };

                string consumerTag = channel.BasicConsume(queueName, true, consumer);

                channel.QueueBind(queueName, EXCHANGE_NAME, "myTopic");
                Console.WriteLine("Listening press ENTER to quit");
                Console.ReadLine();
                channel.QueueUnbind(queueName, EXCHANGE_NAME, "myTopic", null);
            }
        }

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它几乎是从RabbitMQ的官方教程中复制的。请注意，我使用了Sleep方法来模拟长时间任务，并且我发现接收到的事件不能同时触发。换句话说，我只能一个接一个地处理消息，这不是我想要的。我怎样才能使它正确呢？

我们的解决方案基本上是：

consumer.Received += (o,e) => {
    // setup...
    Task.Factory.StartNew(() =>
    {
        // real work done here
    });
};

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也就是说，使用者启动新线程/任务（达到一定限制）。为了简单起见，我省略了任务计数限制逻辑等。

您找到解决方案了吗？