Django jsonresponse和ajax

Django jsonresponse和ajax,ajax,json,django,jsonresponse,Ajax,Json,Django,Jsonresponse,我尝试使用以下代码从django发送JSON响应: def get_symptoms(request): reply = simplejson.dumps({"name":"Amit","address":"B-123 Bangalow","age":23,"phone" :"011-4565763"}) return HttpResponse(reply, mimetype="application/json") <html> <head> <s

我尝试使用以下代码从django发送JSON响应:

def get_symptoms(request):
    reply = simplejson.dumps({"name":"Amit","address":"B-123 Bangalow","age":23,"phone" :"011-4565763"})
    return HttpResponse(reply, mimetype="application/json")
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
</head>
<body>
<script>
$.getJSON('http://127.0.0.1:8000/showsym/', function(data) {var items = [];
$.each(data, function(key, val) {
items.push('<li id="' + key + '">' + val + '</li>');
 });

 $('<ul/>', {'class': 'my-new-list', html: items.join('') }).appendTo('body');});
</script>

</body>
</html>
在客户端,执行以下代码:

def get_symptoms(request):
    reply = simplejson.dumps({"name":"Amit","address":"B-123 Bangalow","age":23,"phone" :"011-4565763"})
    return HttpResponse(reply, mimetype="application/json")
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
</head>
<body>
<script>
$.getJSON('http://127.0.0.1:8000/showsym/', function(data) {var items = [];
$.each(data, function(key, val) {
items.push('<li id="' + key + '">' + val + '</li>');
 });

 $('<ul/>', {'class': 'my-new-list', html: items.join('') }).appendTo('body');});
</script>

</body>
</html>

预期结果是什么,您的结果是什么,以及您在浏览器的控制台日志中看到了什么?我得到的响应是一个空白页面和一个下载了JSON字符串的文件。我想提取对象并使用html标记表示它。