codeigniter中没有给出Ajax调用

Ajax调用不提供给控制器。我在一个页面上有多个表单。

很抱歉，jquery尚未准备好

public function get_all_comments()
{   
    echo 'OK';  
}   

$（函数（）{
$（“#查看_注释”）.submit（函数（e）{
var id=$（“#post_id_for_view_comment”）.val（）；
$.ajax({
url:“index.php/post_comment/get_all_comments”，
类型：“POST”，
数据：{post_id_for_view_comment:id}，
成功：功能（msg）{
警报（msg）；
}
});
e、 预防默认值（）；
});
});

这里有一种新的方法来实现您的需求：

    $(function(){
        $('#view_comment').submit(function(e) {
        var id = $("#post_id_for_view_comment").val();
        $.ajax({
             url: "<?php echo base_url()?>index.php/post_comment/get_all_comments",
             type: "POST",                          
             data: {post_id_for_view_comment:id} ,
             success: function(msg) {
                   alert(msg); 

             }
        });
             e.preventDefault();
        });
     });

---

真的希望我能帮上忙。

您是没有输入var秒分号还是输入错误？

var id=$（“#post_id_for_view_comment”）.val（）
///code>
数据：{post\u id\u for\u view\u comment:id}
和var sec定义的结尾@阿比基谢拉尔
public function get_all_comments()
{   
    echo 'OK';  
}   

    $(function(){
        $('#view_comment').submit(function(e) {
        var id = $("#post_id_for_view_comment").val();
        $.ajax({
             url: "<?php echo base_url()?>index.php/post_comment/get_all_comments",
             type: "POST",                          
             data: {post_id_for_view_comment:id} ,
             success: function(msg) {
                   alert(msg); 

             }
        });
             e.preventDefault();
        });
     });

$('#post_button').click(function(e){
e.preventDefault;
var sec = $('#post_id_for_view_comment').val();
//no need to mention index.php when using site_url() function
 $.post('<?php echo site_url("post_comment/get_all_comments")?>', 
{"post_id_for_view_comment": sec },
         function(data.res == "ok"){ // simple test if it returned ok
         //here you can process your returned data. 
         }, "json"); //**
});

function get_all_comments()
{
//getting your posted sec token.
   $sec = $this->input->post('post_id_for_view_comment'); 
   $data['res'] = "ok";// return anything you like.
// you should use json_encode here because your post's return specified as json. see **
   echo json_encode($data); //$data is checked in the callback function in jquery.
}