使用Ajax的Spring安全性&x2013；记录的用户详细信息

我已经使用AuthenticationEntryPoint和SimpleRulthenticationSuccessHandler通过Ajax实现了用户身份验证

现在我需要将登录的用户名输入到脚本变量中

有人能帮我吗

MyAuthenticationSuccessHandler

public class MyAuthenticationSuccessHandler extends SimpleUrlAuthenticationSuccessHandler {

    private Log log = LogFactory.getLog(MyAuthenticationSuccessHandler.class);

    @Override
    public void onAuthenticationSuccess(HttpServletRequest request, HttpServletResponse response,
            Authentication authentication) throws IOException, ServletException {

        log.info("point-2-->"+authentication.getName()); //this prints what I need.

        // This is actually not an error, but an OK message. It is sent to avoid redirects.
        response.sendError(HttpServletResponse.SC_OK);

    }
}

@RequestMapping(value = "/api/loggeduser", method = RequestMethod.POST)
       public String printWelcome(ModelMap model, Principal principal ) {

        try {

            String name = null;

            if (principal!=null) {

           name = principal.getName();

          }

                model.addAttribute("username", name);



    } catch (Exception e) {
        e.printStackTrace();
    }
  }

我的JavaScript函数

$("#login").on('click', function(e) {
        e.preventDefault();
        $.ajax({url: getHost() + "/j_spring_security_check",
            type: "POST",
            beforeSend: function(xhr) {
                xhr.withCredentials = true;
            },
            data: $("#loginForm").serialize(),
            success: function(response, options) {
                    // We get a success from the server
                    //I need to get user name here
            },
            error: function(result, options) {
                    // We get a failure from the server...
                $(".error").remove();
                $('#j_username').before('<div class="error">Login failed, please try again.</div>');
        }


        });
    });

success: function(response, options) {
                    // We get a success from the server
                    //I need to get user name here

    $.post('/api/loggeduser', function(data) {
           $('#loggeduser').html(data);
        }); 
},

$（“#登录”）。在（'click'，函数（e）{
e、 预防默认值（）；
$.ajax（{url:getHost（）+“/j_spring_security_check”，
类型：“POST”，
发送前：函数（xhr）{
xhr.withCredentials=true；
},
数据：$（“#loginForm”）.serialize（），
成功：功能（响应、选项）{
//我们从服务器上获得了成功
//我需要在这里获取用户名
},
错误：函数（结果、选项）{
//我们从服务器上得到一个故障。。。
$（“.error”）.remove（）；
$（“#j#u username”）。之前（'登录失败，请重试'）；
}
});
});

我已经附上了不同问题的所有相关文件。请访问下面的链接进行检查

我找到了解决办法

简单地说，我做了另一个Ajax调用，并在那里捕获了登录的用户

我的JavaScript函数

$("#login").on('click', function(e) {
        e.preventDefault();
        $.ajax({url: getHost() + "/j_spring_security_check",
            type: "POST",
            beforeSend: function(xhr) {
                xhr.withCredentials = true;
            },
            data: $("#loginForm").serialize(),
            success: function(response, options) {
                    // We get a success from the server
                    //I need to get user name here
            },
            error: function(result, options) {
                    // We get a failure from the server...
                $(".error").remove();
                $('#j_username').before('<div class="error">Login failed, please try again.</div>');
        }


        });
    });

success: function(response, options) {
                    // We get a success from the server
                    //I need to get user name here

    $.post('/api/loggeduser', function(data) {
           $('#loggeduser').html(data);
        }); 
},

loggeduser控制器

public class MyAuthenticationSuccessHandler extends SimpleUrlAuthenticationSuccessHandler {

    private Log log = LogFactory.getLog(MyAuthenticationSuccessHandler.class);

    @Override
    public void onAuthenticationSuccess(HttpServletRequest request, HttpServletResponse response,
            Authentication authentication) throws IOException, ServletException {

        log.info("point-2-->"+authentication.getName()); //this prints what I need.

        // This is actually not an error, but an OK message. It is sent to avoid redirects.
        response.sendError(HttpServletResponse.SC_OK);

    }
}

@RequestMapping(value = "/api/loggeduser", method = RequestMethod.POST)
       public String printWelcome(ModelMap model, Principal principal ) {

        try {

            String name = null;

            if (principal!=null) {

           name = principal.getName();

          }

                model.addAttribute("username", name);



    } catch (Exception e) {
        e.printStackTrace();
    }
  }

我找到了解决办法

简单地说，我做了另一个Ajax调用，并在那里捕获了登录的用户

我的JavaScript函数

$("#login").on('click', function(e) {
        e.preventDefault();
        $.ajax({url: getHost() + "/j_spring_security_check",
            type: "POST",
            beforeSend: function(xhr) {
                xhr.withCredentials = true;
            },
            data: $("#loginForm").serialize(),
            success: function(response, options) {
                    // We get a success from the server
                    //I need to get user name here
            },
            error: function(result, options) {
                    // We get a failure from the server...
                $(".error").remove();
                $('#j_username').before('<div class="error">Login failed, please try again.</div>');
        }


        });
    });

success: function(response, options) {
                    // We get a success from the server
                    //I need to get user name here

    $.post('/api/loggeduser', function(data) {
           $('#loggeduser').html(data);
        }); 
},

loggeduser控制器

public class MyAuthenticationSuccessHandler extends SimpleUrlAuthenticationSuccessHandler {

    private Log log = LogFactory.getLog(MyAuthenticationSuccessHandler.class);

    @Override
    public void onAuthenticationSuccess(HttpServletRequest request, HttpServletResponse response,
            Authentication authentication) throws IOException, ServletException {

        log.info("point-2-->"+authentication.getName()); //this prints what I need.

        // This is actually not an error, but an OK message. It is sent to avoid redirects.
        response.sendError(HttpServletResponse.SC_OK);

    }
}

@RequestMapping(value = "/api/loggeduser", method = RequestMethod.POST)
       public String printWelcome(ModelMap model, Principal principal ) {

        try {

            String name = null;

            if (principal!=null) {

           name = principal.getName();

          }

                model.addAttribute("username", name);



    } catch (Exception e) {
        e.printStackTrace();
    }
  }