Amazon redshift 红移中特定表的查询权限（组和用户）

我正在尝试查找一个查询，该查询允许我以红移方式获取组和用户对特定表的当前权限。我知道如何进行实际的授权，但我花了很长时间找到正确的表来查询以获得现有权限

其他资料：

这将在级联删除并重新创建表的编程操作期间使用，以确保在删除之前重新应用相同的权限。如果有一个选项可以在Python中不使用conn.execute查询来实现这一点，我也愿意这样做

编辑：

我以前确实找到了下面的查询，我尝试了一个简短的快速版本，看看是否可以获取组：

SELECT * 
FROM 
(
SELECT 
    schemaname
    ,objectname
    ,usename
        ,groname
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'select') AND HAS_TABLE_PRIVILEGE(grp.groname, fullobj, 'select') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS sel
FROM
    (
    SELECT schemaname, 't' AS obj_type, tablename AS objectname, schemaname + '.' + tablename AS fullobj FROM pg_tables
    UNION
    SELECT schemaname, 'v' AS obj_type, viewname AS objectname, schemaname + '.' + viewname AS fullobj FROM pg_views
    ) AS objs
    ,(SELECT * FROM pg_user) AS usrs
        ,(SELECT * FROM pg_group) AS grp
ORDER BY fullobj
)
WHERE sel = true
and objectname = 'table_name'

---

这会给我一个错误，说它找不到作为组名的用户名。

您可以使用以下带有objectname筛选器的查询来查找特定表的权限

SELECT * 
FROM 
(
SELECT 
    schemaname
    ,objectname
    ,usename
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'select') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS sel
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'insert') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS ins
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'update') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS upd
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'delete') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS del
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'references') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS ref
FROM
    (
    SELECT schemaname, 't' AS obj_type, tablename AS objectname, schemaname + '.' + tablename AS fullobj FROM pg_tables
    UNION
    SELECT schemaname, 'v' AS obj_type, viewname AS objectname, schemaname + '.' + viewname AS fullobj FROM pg_views
    ) AS objs
    ,(SELECT * FROM pg_user) AS usrs
ORDER BY fullobj
)
WHERE (sel = true or ins = true or upd = true or del = true or ref = true)
and objectname = 'my_table'

---

可以将以下查询与objectname筛选器一起使用，以查找特定表的权限

SELECT * 
FROM 
(
SELECT 
    schemaname
    ,objectname
    ,usename
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'select') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS sel
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'insert') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS ins
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'update') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS upd
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'delete') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS del
    ,HAS_TABLE_PRIVILEGE(usrs.usename, fullobj, 'references') AND has_schema_privilege(usrs.usename, schemaname, 'usage')  AS ref
FROM
    (
    SELECT schemaname, 't' AS obj_type, tablename AS objectname, schemaname + '.' + tablename AS fullobj FROM pg_tables
    UNION
    SELECT schemaname, 'v' AS obj_type, viewname AS objectname, schemaname + '.' + viewname AS fullobj FROM pg_views
    ) AS objs
    ,(SELECT * FROM pg_user) AS usrs
ORDER BY fullobj
)
WHERE (sel = true or ins = true or upd = true or del = true or ref = true)
and objectname = 'my_table'

---

我终于找到了一些我能够为小组挑选的东西，并将它们拼凑在一起：

SELECT
    namespace, item, type, groname 
FROM
    (
    SELECT
        use.usename AS subject,
        nsp.nspname AS NAMESPACE,
        cls.relname AS item,
        cls.relkind AS TYPE,
        use2.usename AS OWNER,
        cls.relacl 
    FROM
        pg_user use
        CROSS JOIN pg_class cls
        LEFT JOIN pg_namespace nsp ON cls.relnamespace = nsp.oid
        LEFT JOIN pg_user use2 ON cls.relowner = use2.usesysid 
    WHERE
        cls.relowner = use.usesysid 
        AND nsp.nspname NOT IN ( 'pg_catalog', 'pg_toast', 'information_schema' ) 
        AND nsp.nspname IN ( 'schema' ) 
        AND relacl IS NOT NULL 
    ORDER BY
        subject,
        NAMESPACE,
        item 
    )
    JOIN pg_group pu ON array_to_string( relacl, '|' ) LIKE'%' || pu.groname || '%'

---

除了

我终于找到了一些我能够为小组挑选的东西，并将它们散列在一起：

SELECT
    namespace, item, type, groname 
FROM
    (
    SELECT
        use.usename AS subject,
        nsp.nspname AS NAMESPACE,
        cls.relname AS item,
        cls.relkind AS TYPE,
        use2.usename AS OWNER,
        cls.relacl 
    FROM
        pg_user use
        CROSS JOIN pg_class cls
        LEFT JOIN pg_namespace nsp ON cls.relnamespace = nsp.oid
        LEFT JOIN pg_user use2 ON cls.relowner = use2.usesysid 
    WHERE
        cls.relowner = use.usesysid 
        AND nsp.nspname NOT IN ( 'pg_catalog', 'pg_toast', 'information_schema' ) 
        AND nsp.nspname IN ( 'schema' ) 
        AND relacl IS NOT NULL 
    ORDER BY
        subject,
        NAMESPACE,
        item 
    )
    JOIN pg_group pu ON array_to_string( relacl, '|' ) LIKE'%' || pu.groname || '%'

---

除了

我的问题没有指定，现在我需要更新它，但我正在查找组权限和用户权限我的问题没有指定，现在我需要更新它，但我正在寻找组权限和用户权限。我将使用mdem7中的答案来回答用户。我将使用mdem7中的答案来回答用户。