Android 从自定义基于类的列表中删除重复元素(哈希集解决方案不起作用)?
我有一个自定义列表,其中包含具有名称和电话号码的类对象。。现在的问题是复制品太多了。我需要根据电话号码删除所有副本 当我尝试这种方法时:Android 从自定义基于类的列表中删除重复元素(哈希集解决方案不起作用)?,android,list,duplicates,Android,List,Duplicates,我有一个自定义列表,其中包含具有名称和电话号码的类对象。。现在的问题是复制品太多了。我需要根据电话号码删除所有副本 当我尝试这种方法时: list = getContacts(); list = new ArrayList<ModelContact>(new LinkedHashSet<ModelContact>(list)); listView.setAdapter(new ContactsAdapter(this, list)); 联系
list = getContacts();
list = new ArrayList<ModelContact>(new LinkedHashSet<ModelContact>(list));
listView.setAdapter(new ContactsAdapter(this, list));
联系人列表:
public class ContactsList extends ActionBarActivity {
private ListView listView;
ProgressBar progressBar;
List<ModelContact> list;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.list_contacts);
listView = (ListView) findViewById(R.id.contacts_list);
progressBar = (ProgressBar) findViewById(R.id.progressBar);
list = new ArrayList<>();
list = getContacts();
list = new ArrayList<ModelContact>(new LinkedHashSet<ModelContact>(list));
listView.setAdapter(new ContactsAdapter(this, list));
}
private List<ModelContact> getContacts() {
ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
List<ModelContact> modelContacts = new ArrayList<>();
if (cur.getCount() > 0) {
ModelContact obj = new ModelContact();
while (cur.moveToNext()) {
String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer.parseInt(cur.getString(
cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor pCur = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id}, null);
while (pCur.moveToNext()) {
String phoneNo = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
Bitmap bmp = retrieveContactPhoto(id);
if (bmp == null) {
System.out.println(name + "is \t null");
} else {
Toast.makeText(this, "not null \t" + phoneNo, Toast.LENGTH_SHORT).show();
}
String imagecon = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
obj.set_id(id);
obj.setName(name);
obj.setContactNumber(phoneNo);
obj.setImageUri(bmp);
modelContacts.add(obj);
System.out.println("Name: " + name + ", Phone No: " + phoneNo);
//Toast.makeText(NativeContentProvider.this, "Name: " + name + ", Phone No: " + phoneNo, Toast.LENGTH_SHORT).show();
}
pCur.close();
}
}
}
System.out.print("Size:::" + modelContacts.size());
return modelContacts;
}
private Bitmap retrieveContactPhoto(String contactID) {
Bitmap photo = null;
try {
InputStream inputStream = ContactsContract.Contacts.openContactPhotoInputStream(getContentResolver(),
ContentUris.withAppendedId(ContactsContract.Contacts.CONTENT_URI, new Long(contactID)));
if (inputStream != null) {
photo = BitmapFactory.decodeStream(inputStream);
return photo;
}
if (inputStream != null)
inputStream.close();
} catch (IOException e) {
e.printStackTrace();
return null;
}
return null;
}
}
首先,您需要重写ModelContact类中的equals和hashcode方法。在重写equals和hashcode方法时,需要注意电话号码 然后您可以使用下面的代码删除重复的元素
list = new ArrayList<ModelContact>(new LinkedHashSet<ModelContact>(list))
我仍然得到相同的结果,即列表中的1项。查看更新的代码。即使您的代码也应该可以工作,您只需更新map.putInteger.parseIntays.get\u phoneNo,ays;有关更多信息,请参阅此链接。问题是no.的格式不是整数,而是字符串,有时有特殊字符+或有时有空格。如何实现它?
list = new ArrayList<ModelContact>(new LinkedHashSet<ModelContact>(list))