Android 消息未显示在模拟器屏幕上

以下是查找当前位置的代码，但按下Retrieve按钮后屏幕上不会显示任何内容
我已重置adb并尝试手动从emulator控件发送数据。但当我使用emulator控件发送数据时，emulator会重新启动，但不会显示主屏幕。
请帮忙。提前谢谢

public class LbsGeocodingActivity extends Activity {

    private static final long MINIMUM_DISTANCE_CHANGE_FOR_UPDATES = 1; // in Meters

    private static final long MINIMUM_TIME_BETWEEN_UPDATES = 1000; // in Milliseconds

    protected LocationManager locationManager;

    protected Button retrieveLocationButton;

    public void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);

        setContentView(R.layout.main);

        retrieveLocationButton = (Button) findViewById(R.id.retrieve_location_button);

        locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);

        locationManager.requestLocationUpdates(
                LocationManager.GPS_PROVIDER,
                MINIMUM_TIME_BETWEEN_UPDATES,
                MINIMUM_DISTANCE_CHANGE_FOR_UPDATES,
                new MyLocationListener()

        );
    retrieveLocationButton.setOnClickListener(new OnClickListener() {

            public void onClick(View v) {
                showCurrentLocation();
            }
    });       

    }   

    protected void showCurrentLocation() {
        Location location = locationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
        if (location != null) {
            String message = String.format(
                    "Current Location \n Longitude: %1$s \n Latitude: %2$s",
                    location.getLongitude(), location.getLatitude()
            );
            Toast.makeText(LbsGeocodingActivity.this, message,
                    Toast.LENGTH_LONG).show();
        }
    }  

    private class MyLocationListener implements LocationListener {
        public void onLocationChanged(Location location) {
            String message = String.format(
                    "New Location \n Longitude: %1$s \n Latitude: %2$s",
                    location.getLongitude(), location.getLatitude()
            );

            Toast.makeText(LbsGeocodingActivity.this, message, Toast.LENGTH_LONG).show();
        }

        public void onStatusChanged(String s, int i, Bundle b) {
            Toast.makeText(LbsGeocodingActivity.this, "Provider status changed",
                    Toast.LENGTH_LONG).show();
        }

        public void onProviderDisabled(String s) {
            Toast.makeText(LbsGeocodingActivity.this,
                    "Provider disabled by the user. GPS turned off",
                    Toast.LENGTH_LONG).show();
        }

        public void onProviderEnabled(String s) {
            Toast.makeText(LbsGeocodingActivity.this,
                    "Provider enabled by the user. GPS turned on",
                    Toast.LENGTH_LONG).show();
        }

    }
}

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在您的代码中，您可能没有收到当前位置（这是因为在中，您需要手动推送您的位置）

只需在showCurrentLocation（）中使用else case并检查location对象是否为null，如下所示

protected void showCurrentLocation() {
    Location location = locationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
    if (location != null) {
        String message = String.format(
                "Current Location \n Longitude: %1$s \n Latitude: %2$s",
                location.getLongitude(), location.getLatitude()
        );

    Toast.makeText(LbsGeocodingActivity.this, message,
                Toast.LENGTH_LONG).show();
    }else{
       Toast.makeText(LbsGeocodingActivity.this, "location is null",
                Toast.LENGTH_LONG).show();
    }
}  

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在我们第一次尝试使用位置传感器时，我们遇到了类似的问题。为了从GPS获得最佳效果，有两件事最有帮助

在模拟器上，使用Location Location=locationManager.getLastKnownLocation（locationManager.GPS\u提供程序）导致大量强制关闭

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最重要的是。通过telnet输入gps数据要稳定得多

telnet localhost 5554

（您可以在模拟器窗口标题上看到端口）。新gps定位的命令是：

geo fix lat lng

您是对的，它显示“位置为空”，然后问题在哪里，gps不起作用我认为模拟器gps不起作用，但你有模拟器控制，你可以手动将你的lat ans长推以进行测试。添加了模拟器控制的链接我使用模拟器控制推拉lat n lon，但它不起作用。我想使用gpx。这行吗？仍然显示“位置为空”推送数据为long=-122.0841 lat=37.44006：(