Android 如何在触摸时获取recyclerView项目的位置

Android 如何在触摸时获取recyclerView项目的位置,android,navigation-drawer,android-recyclerview,Android,Navigation Drawer,Android Recyclerview,我有一个recyclerView在DrawerLayout里面。每行项目都有一个图像视图,图标和一个文本框,文本。我使用addonimtouchlistener在用户单击时检测行项目的位置,以便打开一个新片段。这是我的代码,来自addonimtouchlistener: mRecyclerView.addOnItemTouchListener(new RecyclerView.OnItemTouchListener() { @Override public boo

我有一个
recyclerView
DrawerLayout
里面。每行项目都有一个
图像视图
,图标和一个
文本框
,文本。我使用
addonimtouchlistener
在用户单击时检测行项目的位置,以便打开一个新片段。这是我的代码,来自
addonimtouchlistener

mRecyclerView.addOnItemTouchListener(new RecyclerView.OnItemTouchListener() {
        @Override
        public boolean onInterceptTouchEvent(RecyclerView rv, MotionEvent e) {
            View item = rv.findChildViewUnder(e.getX(),e.getY()); //finding the view that clicked , using coordinates X and Y
            int position = rv.getChildLayoutPosition(item); //getting the position of the item inside the list
            //Log.d("billy",String.valueOf(position));
            onListViewItemClick(position);
            mDrawer.closeDrawers(); // closing the navigation drawer
            return true;
        }

        @Override
        public void onTouchEvent(RecyclerView rv, MotionEvent e) {

        }

        @Override
        public void onRequestDisallowInterceptTouchEvent(boolean disallowIntercept) {

        }
    });
这就是方法
onListViewItemClick

public void onListViewItemClick(int position) {
    DrawerItem data = mList.get(position); //Item of the recycler View at specific position
    Bundle lbundle = new Bundle();
    lFragmentManager = getFragmentManager();
    lFragment = lFragmentManager.findFragmentById(R.id.frame_container);
    lFragment = new FragmentHome();
    lbundle.putSerializable("Item", data); // sending to fragment the Item of the Recycler View , which pressed
    lFragment.setArguments(lbundle);
    //To the fragment
    lFragmentManager.beginTransaction().replace(R.id.frame_container ,lFragment ).commit();
}
问题是,只有当用户单击导航抽屉行项目的
imageView
时,此实现才有效。如果用户单击行项目的
TextView
,则变量位置的值为-1。我认为方法
查找childviewunder(e.getX(),e.getY())
只返回
imageView
,而不是两者都返回。我想要
findChildViewUnder(e.getx(),e.getY())
返回视图组

这是定义导航抽屉的每一行项目的XML文件:

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
          android:orientation="horizontal"
          android:layout_width="match_parent"
          android:layout_height="match_parent"
          android:background="?android:attr/selectableItemBackground">
<LinearLayout
    android:id="@+id/inner_layout"
    android:layout_width="40dp"
    android:layout_height="wrap_content"
    android:layout_alignBottom="@+id/nv_title"
    android:layout_alignTop="@+id/nv_title"
    android:layout_alignParentLeft="true"
    android:layout_alignParentStart="true">

    <ImageView
        android:layout_width="25dp"
        android:layout_height="25dp"
        android:id="@+id/nv_image"
        android:background="@android:color/transparent"
        android:scaleType="fitXY"
        android:layout_marginLeft="15dp"
        android:layout_gravity="center"/>

</LinearLayout>

<TextView
    android:id="@+id/nv_title"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:paddingLeft="13dp"
    android:minHeight="?android:attr/listPreferredItemHeightSmall"
    android:textAppearance="?android:attr/textAppearanceListItemSmall"
    android:gravity="center_vertical"
    android:layout_centerVertical="true"
    android:layout_alignParentRight="true"
    android:layout_alignParentEnd="true"
    android:layout_toEndOf="@+id/inner_layout"
    android:layout_gravity="center"
    android:singleLine="true"
    android:ellipsize="end"
    android:layout_toRightOf="@+id/inner_layout" />

    </RelativeLayout>


谢谢你的帮助

如果将onClick listener设置为on
onBindViewHolder

@Override
public void onBindViewHolder(RecyclerView.ViewHolder holder, int position) {
//TODO: Use position here.
}

您可以扩展ViewHolder类,以便在需要单击的项目部分上有一个单击侦听器(即,使用容器捕获“项目单击”)。单击后,您可以对事件执行任何您喜欢的操作,并且准确的位置将是来自ViewHolder本身的
getAdapterPosition()

如果您注册了
ItemTouchListener
,您可以获得如下视图位置:

public class RecyclerItemClickListener implements RecyclerView.OnItemTouchListener {
    private static final String TAG = RecyclerItemClickListener.class.getSimpleName();

    public void setListener(OnItemClickListener mListener) {
        this.mListener = mListener;
    }

    private OnItemClickListener mListener;

    public RecyclerItemClickListener(Context context) {
        this(context, null);
    }


    GestureDetector mGestureDetector;

    public RecyclerItemClickListener(Context context, OnItemClickListener listener) {
        mListener = listener;
        mGestureDetector = new GestureDetector(context, new GestureDetector.SimpleOnGestureListener() {
            @Override public boolean onSingleTapUp(MotionEvent e) {
                return true;
            }
        });
    }

    @Override public boolean onInterceptTouchEvent(RecyclerView view, MotionEvent e) {
        View childView = view.findChildViewUnder(e.getX(), e.getY());

        if (childView != null && mListener != null && mGestureDetector.onTouchEvent(e)) {
            mListener.onItemClick(view, childView, view.getChildAdapterPosition(childView));
        }
        return false;
    }

    @Override public void onTouchEvent(RecyclerView view, MotionEvent motionEvent) { }

    @Override
    public void onRequestDisallowInterceptTouchEvent(boolean disallowIntercept) {

    }
}

语句
view.getChildAdapterPosition(childView)
是来自
RecyclerView
的方法,返回被触摸视图在适配器中的位置

rv.findChildViewUnder(e.getX(),e.getY())在我的case@Vasilisfoo这个答案很有效。请标记它。它给出-1 bcoz视图项=rv.findChildViewUnder(e.getX(),e.getY());返回空值