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从Android我想用POST方法调用API

android api post

从Android我想用POST方法调用API,android,api,post,Android,Api,Post,当我提交来自邮递员的请求时，我得到了API的响应，如图所示 screenshot1.jpg=我需要传递的数据 screenshot2.jpg=我们得到的结果 我试着用下面的代码通过安卓系统给他们打电话，但不起作用 JSONObject login = new JSONObject(); login.put("username", userName); login.put("password", password); login.put("platform", "ANDROID"); logi

当我提交来自邮递员的请求时，我得到了API的响应，如图所示

screenshot1.jpg=我需要传递的数据 screenshot2.jpg=我们得到的结果

我试着用下面的代码通过安卓系统给他们打电话，但不起作用

JSONObject login = new JSONObject();
login.put("username", userName);
login.put("password", password);
login.put("platform", "ANDROID");
login.put("location", "56.1603092,10.2177147");

String str = WebServices.excutePost(url, login);


public static String excutePost(String targetURL, JSONObject urlParameters) {
    URL url;
    HttpURLConnection connection = null;
    try {


        //Create connection
        url = new URL(targetURL);
        connection = (HttpURLConnection) url.openConnection();
        connection.setRequestMethod("POST");
        connection.setRequestProperty("Content-Type",
                "application/raw");

        connection.setRequestProperty("Content-Length", "" +
                Integer.toString(urlParameters.toString().getBytes().length));
        connection.setRequestProperty("Content-Language", "en-US");


        connection.setUseCaches(false);
        connection.setDoInput(true);
        connection.setDoOutput(true);


        //Send request

        OutputStream out = new BufferedOutputStream(connection.getOutputStream());
        BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
        writer.write(String.valueOf(urlParameters.toString().getBytes("UTF-8")));
        out.close();
        //connection.disconnect();

        //Get Response
        InputStream is = connection.getInputStream();
        BufferedReader rd = new BufferedReader(new InputStreamReader(is));
        String line;
        StringBuffer response = new StringBuffer();
        while ((line = rd.readLine()) != null) {
            response.append(line);
            response.append('\r');
        }
        rd.close();
        return response.toString();

    } catch (Exception e) {

        e.printStackTrace();
        return null;

    } finally {

        if (connection != null) {
            connection.disconnect();
        }
    }
}
您可以使用以下方法：

public String executePost(String targetURL,String urlParameters) {
    int timeout=5000;
    URL url;
    HttpURLConnection connection = null;
    try {
        // Create connection

        url = new URL(targetURL);
        connection = (HttpURLConnection) url.openConnection();
        connection.setRequestMethod("POST");
        connection.setRequestProperty("Content-Type",
                "application/json");

        connection.setRequestProperty("Content-Length",
                "" + Integer.toString(urlParameters.getBytes().length));
        connection.setRequestProperty("Content-Language", "en-US");

        connection.setUseCaches(false);
        connection.setDoInput(true);
        connection.setDoOutput(true);
        connection.setConnectTimeout(timeout);
        connection.setReadTimeout(timeout);

        // Send request
        DataOutputStream wr = new DataOutputStream(
                connection.getOutputStream());
        wr.writeBytes(urlParameters);
        wr.flush();
        wr.close();

        // Get Response
        InputStream is = connection.getInputStream();
        BufferedReader rd = new BufferedReader(new InputStreamReader(is));
        String line;
        StringBuffer response = new StringBuffer();
        while ((line = rd.readLine()) != null) {
            response.append(line);
            response.append('\r');
        }
        rd.close();
        return response.toString();

    } catch (SocketTimeoutException ex) {
        ex.printStackTrace();

    } catch (MalformedURLException ex) {
        Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (UnknownHostException e) {
        e.printStackTrace();
    } catch (IOException ex) {

        Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (Exception e) {
        e.printStackTrace();
    } finally {

        if (connection != null) {
            connection.disconnect();
        }
    }
    return null;
}
您可以创建URL参数，如：

JSONObject loginParams = new JSONObject();
loginParams .put("username", userName);
loginParams .put("password", password);
loginParams .put("platform", "ANDROID");
loginParams .put("location", "56.1603092,10.2177147");
调用如下方法：

executePost(serviceURL,loginParams.toString());
您可以使用以下方法：

public String executePost(String targetURL,String urlParameters) {
    int timeout=5000;
    URL url;
    HttpURLConnection connection = null;
    try {
        // Create connection

        url = new URL(targetURL);
        connection = (HttpURLConnection) url.openConnection();
        connection.setRequestMethod("POST");
        connection.setRequestProperty("Content-Type",
                "application/json");

        connection.setRequestProperty("Content-Length",
                "" + Integer.toString(urlParameters.getBytes().length));
        connection.setRequestProperty("Content-Language", "en-US");

        connection.setUseCaches(false);
        connection.setDoInput(true);
        connection.setDoOutput(true);
        connection.setConnectTimeout(timeout);
        connection.setReadTimeout(timeout);

        // Send request
        DataOutputStream wr = new DataOutputStream(
                connection.getOutputStream());
        wr.writeBytes(urlParameters);
        wr.flush();
        wr.close();

        // Get Response
        InputStream is = connection.getInputStream();
        BufferedReader rd = new BufferedReader(new InputStreamReader(is));
        String line;
        StringBuffer response = new StringBuffer();
        while ((line = rd.readLine()) != null) {
            response.append(line);
            response.append('\r');
        }
        rd.close();
        return response.toString();

    } catch (SocketTimeoutException ex) {
        ex.printStackTrace();

    } catch (MalformedURLException ex) {
        Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (UnknownHostException e) {
        e.printStackTrace();
    } catch (IOException ex) {

        Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
    } catch (Exception e) {
        e.printStackTrace();
    } finally {

        if (connection != null) {
            connection.disconnect();
        }
    }
    return null;
}
您可以创建URL参数，如：

JSONObject loginParams = new JSONObject();
loginParams .put("username", userName);
loginParams .put("password", password);
loginParams .put("platform", "ANDROID");
loginParams .put("location", "56.1603092,10.2177147");
调用如下方法：

executePost(serviceURL,loginParams.toString());
您可以使用该库更容易地实现与REST服务的网络通信

顺便说一下，您可以尝试我的解决方案来解决您的问题：

  • 首先创建一个executeHttp方法

            private JSONObject executeHttp(HttpUriRequest request, Context context) throws ClientProtocolException, IOException {
        HttpParams httpParameters = new BasicHttpParams();
            // Set the timeout in milliseconds until a connection is established.
            // The default value is zero, that means the timeout is not used.
            int timeoutConnection = 3000;
            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
            // Set the default socket timeout (SO_TIMEOUT)
            // in milliseconds which is the timeout for waiting for data.
            int timeoutSocket = 10000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

            DefaultHttpClient client = new DefaultHttpClient(httpParameters);
            // add your header in here - I saw your header has 7 params
            request.addHeader("Authorization", getToken());
            request.addHeader("APIKey", API_KEY);
            request.addHeader("Content-Type", "application/x-www-form-urlencoded");
            request.addHeader("X-Request-Mime-Type", "application/json;");
            HttpResponse execute = client.execute(request);
            InputStream content = execute.getEntity().getContent();
            // implement your handle response here, below is just an example
            try {
                 return new JSONObject().put("content", this.convertStreamToByteArray(content));
            } catch (JSONException e) {
            //Crashlytics.logException(e);
                 Log.e(LOG_TAG, "Error converting stream to byte array: " + e.getMessage());
                 return new JSONObject();

            }
        }
然后创建一个方法来处理POST请求

public JSONObject doPost(List<NameValuePair> headerParams, List<NameValuePair> parameters, String url, Context context) throws ClientProtocolException, IOException {
        HttpPost httpPost = new HttpPost(url);
        // add the header if needed
        if (headerParams != null) {
            for (NameValuePair headerParam: headerParams) {
                httpPost.addHeader(headerParam.getName(), headerParam.getValue());
            }
        }
        httpPost.setEntity(new UrlEncodedFormEntity(parameters, "UTF-8"));

        return executeHttp(httpPost, context);
    }
使用nameValuePairs创建的

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("username", userName));
            nameValuePairs.add(new BasicNameValuePair("password", password));
            nameValuePairs.add(new BasicNameValuePair("platform", "ANDROID"));
            nameValuePairs.add(new BasicNameValuePair("location", "56.1603092,10.2177147"));

List nameValuePairs=new ArrayList（）；
添加（新的BasicNameValuePair（“用户名”，username））；
添加（新的BasicNameValuePair（“密码”，password））；
添加（新的BasicNameValuePair（“平台”、“ANDROID”）；
添加（新的BasicNameValuePair（“位置”，“56.1603092,10.2177147”）；
您可以使用库来更轻松地实现与REST服务的网络通信

顺便说一下，您可以尝试我的解决方案来解决您的问题：

  • 首先创建一个executeHttp方法

            private JSONObject executeHttp(HttpUriRequest request, Context context) throws ClientProtocolException, IOException {
        HttpParams httpParameters = new BasicHttpParams();
            // Set the timeout in milliseconds until a connection is established.
            // The default value is zero, that means the timeout is not used.
            int timeoutConnection = 3000;
            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
            // Set the default socket timeout (SO_TIMEOUT)
            // in milliseconds which is the timeout for waiting for data.
            int timeoutSocket = 10000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);

            DefaultHttpClient client = new DefaultHttpClient(httpParameters);
            // add your header in here - I saw your header has 7 params
            request.addHeader("Authorization", getToken());
            request.addHeader("APIKey", API_KEY);
            request.addHeader("Content-Type", "application/x-www-form-urlencoded");
            request.addHeader("X-Request-Mime-Type", "application/json;");
            HttpResponse execute = client.execute(request);
            InputStream content = execute.getEntity().getContent();
            // implement your handle response here, below is just an example
            try {
                 return new JSONObject().put("content", this.convertStreamToByteArray(content));
            } catch (JSONException e) {
            //Crashlytics.logException(e);
                 Log.e(LOG_TAG, "Error converting stream to byte array: " + e.getMessage());
                 return new JSONObject();

            }
        }
然后创建一个方法来处理POST请求

public JSONObject doPost(List<NameValuePair> headerParams, List<NameValuePair> parameters, String url, Context context) throws ClientProtocolException, IOException {
        HttpPost httpPost = new HttpPost(url);
        // add the header if needed
        if (headerParams != null) {
            for (NameValuePair headerParam: headerParams) {
                httpPost.addHeader(headerParam.getName(), headerParam.getValue());
            }
        }
        httpPost.setEntity(new UrlEncodedFormEntity(parameters, "UTF-8"));

        return executeHttp(httpPost, context);
    }
使用nameValuePairs创建的

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("username", userName));
            nameValuePairs.add(new BasicNameValuePair("password", password));
            nameValuePairs.add(new BasicNameValuePair("platform", "ANDROID"));
            nameValuePairs.add(new BasicNameValuePair("location", "56.1603092,10.2177147"));

List nameValuePairs=new ArrayList（）；
添加（新的BasicNameValuePair（“用户名”，username））；
添加（新的BasicNameValuePair（“密码”，password））；
添加（新的BasicNameValuePair（“平台”、“ANDROID”）；
添加（新的BasicNameValuePair（“位置”，“56.1603092,10.2177147”）；
问题是使用stringbuffer类，我使用string获得响应，它工作得非常好。谢谢大家的评论和回答。

问题是使用stringbuffer类，我使用string获得响应，它工作得非常好。谢谢大家的评论和回答。

你能详细说明一下“不工作”吗？它在做什么或不做什么？是否有错误消息？我认为您的内容类型应该是application/jsonce如果可能的话，您可以为问题提供stacktrace吗？您是否尝试过output.writeBytes（String.valueOf（urlParameters.toString（）.getBytes（“UTF-8”）；你能详细说明一下“不工作”吗？它在做什么或不做什么？是否有错误消息？我认为您的内容类型应该是application/jsonce如果可能的话，您可以为问题提供stacktrace吗？您是否尝试过output.writeBytes（String.valueOf（urlParameters.toString（）.getBytes（“UTF-8”）；