如何在Android中使用InputFilter限制EditText中的字符?
我只想将字符限制为0-9、a-z、a-z和空格键。设置inputtype我可以限制为数字,但我无法找出Inputfilter查看文档的方式。如果您将Inputfilter子类化,则可以创建自己的Inputfilter,以过滤掉任何非字母数字字符 InputFilter接口有一个方法,如何在Android中使用InputFilter限制EditText中的字符?,android,android-edittext,Android,Android Edittext,我只想将字符限制为0-9、a-z、a-z和空格键。设置inputtype我可以限制为数字,但我无法找出Inputfilter查看文档的方式。如果您将Inputfilter子类化,则可以创建自己的Inputfilter,以过滤掉任何非字母数字字符 InputFilter接口有一个方法,filter(CharSequence source、int start、int end、Spand dest、int dstart、int dend),它为您提供了所需的所有信息,让您知道在EditText中输入了
filter(CharSequence source、int start、int end、Spand dest、int dstart、int dend)
,它为您提供了所需的所有信息,让您知道在EditText中输入了哪些字符
创建自己的InputFilter后,可以通过调用setFilters(…)将其分配给EditText
,int,int,android.text.span,int,int)我在另一个论坛上找到了这个。像冠军一样工作
InputFilter filter = new InputFilter() {
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend) {
for (int i = start; i < end; i++) {
if (!Character.isLetterOrDigit(source.charAt(i))) {
return "";
}
}
return null;
}
};
edit.setFilters(new InputFilter[] { filter });
InputFilter过滤器=新的InputFilter(){
公共CharSequence筛选器(CharSequence源、int开始、int结束、,
跨越目的地、内部数据起点、内部数据起点){
for(int i=start;i
除了可接受的答案外,还可以使用例如:android:inputType=“textCapCharacters”
作为
的属性,以便只接受大写字符(和数字)。可以使用setonkeylister
。在这个方法中,我们可以自定义输入edittext
在显示字典建议的Android版本中,InputFilter有点复杂。有时在源
参数中会出现SpannableStringBuilder
,有时会出现一个普通的字符串
以下InputFilter
应该可以工作。请随意改进此代码
new InputFilter() {
@Override
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend) {
if (source instanceof SpannableStringBuilder) {
SpannableStringBuilder sourceAsSpannableBuilder = (SpannableStringBuilder)source;
for (int i = end - 1; i >= start; i--) {
char currentChar = source.charAt(i);
if (!Character.isLetterOrDigit(currentChar) && !Character.isSpaceChar(currentChar)) {
sourceAsSpannableBuilder.delete(i, i+1);
}
}
return source;
} else {
StringBuilder filteredStringBuilder = new StringBuilder();
for (int i = start; i < end; i++) {
char currentChar = source.charAt(i);
if (Character.isLetterOrDigit(currentChar) || Character.isSpaceChar(currentChar)) {
filteredStringBuilder.append(currentChar);
}
}
return filteredStringBuilder.toString();
}
}
}
newInputFilter(){
@凌驾
公共CharSequence筛选器(CharSequence源、int开始、int结束、,
跨越目的地、内部数据起点、内部数据起点){
if(SpannableStringBuilder的源实例){
SpannableStringBuilder sourceAsSpannableBuilder=(SpannableStringBuilder)源;
对于(inti=end-1;i>=start;i--){
char currentChar=源字符(i);
如果(!Character.isleterOrdGit(currentChar)和&!Character.isSpaceChar(currentChar)){
sourceAsSpannableBuilder.delete(i,i+1);
}
}
返回源;
}否则{
StringBuilder filteredStringBuilder=新建StringBuilder();
对于(inti=start;i
简单得多:
<EditText
android:inputType="text"
android:digits="0,1,2,3,4,5,6,7,8,9,*,qwertzuiopasdfghjklyxcvbnm" />
由于某些原因,android.text.LoginFilter类的构造函数是包范围的,因此您不能直接扩展它(即使它与此代码相同)。但是您可以扩展LoginFilter.UsernameFilterGeneric!那么你就有这个:
class ABCFilter extends LoginFilter.UsernameFilterGeneric {
public UsernameFilter() {
super(false); // false prevents not-allowed characters from being appended
}
@Override
public boolean isAllowed(char c) {
if ('A' <= c && c <= 'C')
return true;
if ('a' <= c && c <= 'c')
return true;
return false;
}
}
类ABCFilter扩展了LoginFilter.UsernameFilterGeneric{
公共UsernameFilter(){
super(false);//false防止追加不允许的字符
}
@凌驾
允许使用公共布尔值(字符c){
如果('A'当我需要防止用户在EditText中输入空字符串时,这个简单的解决方案对我有效。当然,您可以添加更多字符:
InputFilter textFilter = new InputFilter() {
@Override
public CharSequence filter(CharSequence c, int arg1, int arg2,
Spanned arg3, int arg4, int arg5) {
StringBuilder sbText = new StringBuilder(c);
String text = sbText.toString();
if (text.contains(" ")) {
return "";
}
return c;
}
};
private void setTextFilter(EditText editText) {
editText.setFilters(new InputFilter[]{textFilter});
}
所有张贴的答案都不适用于我。我有自己的解决方案:
InputFilter filter = new InputFilter() {
@Override
public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
boolean keepOriginal = true;
StringBuilder sb = new StringBuilder(end - start);
for (int i = start; i < end; i++) {
char c = source.charAt(i);
if (isCharAllowed(c)) // put your condition here
sb.append(c);
else
keepOriginal = false;
}
if (keepOriginal)
return null;
else {
if (source instanceof Spanned) {
SpannableString sp = new SpannableString(sb);
TextUtils.copySpansFrom((Spanned) source, start, sb.length(), null, sp, 0);
return sp;
} else {
return sb;
}
}
}
private boolean isCharAllowed(char c) {
return Character.isLetterOrDigit(c) || Character.isSpaceChar(c);
}
}
editText.setFilters(new InputFilter[] { filter });
InputFilter过滤器=新的InputFilter(){
@凌驾
公共CharSequence筛选器(CharSequence源、int开始、int结束、跨区目标、int开始、int结束){
布尔值keepOriginal=true;
StringBuilder sb=新的StringBuilder(结束-开始);
for(int i=start;i
这是正确的,最好的解决方法是在XML布局本身中使用以下方法修复它:
<EditText
android:inputType="text"
android:digits="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" />
正如Florian Fröhlich正确指出的那样,它甚至适用于文本视图
<TextView
android:inputType="text"
android:digits="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" />
请注意,
android:digits
中提到的字符只会显示出来,所以请注意不要漏掉任何字符集:)忽略其他人处理过的span内容,为了正确处理字典建议,我发现以下代码是有效的
源代码随着建议的增长而增长,因此在返回任何内容之前,我们必须查看它实际希望我们替换多少字符
如果没有任何无效字符,则返回null,以便进行默认替换
否则,我们需要从实际要放入EditText的子字符串中提取有效字符
InputFilter filter = new InputFilter() {
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend) {
boolean includesInvalidCharacter = false;
StringBuilder stringBuilder = new StringBuilder();
int destLength = dend - dstart + 1;
int adjustStart = source.length() - destLength;
for(int i=start ; i<end ; i++) {
char sourceChar = source.charAt(i);
if(Character.isLetterOrDigit(sourceChar)) {
if(i >= adjustStart)
stringBuilder.append(sourceChar);
} else
includesInvalidCharacter = true;
}
return includesInvalidCharacter ? stringBuilder : null;
}
};
InputFilter过滤器=新的InputFilter(){
公共CharSequence筛选器(CharSequence源、int开始、int结束、,
public class Wordfilter implements InputFilter
{
@Override
public CharSequence filter(CharSequence source, int start, int end,Spanned dest, int dstart, int dend) {
// TODO Auto-generated method stub
boolean append = false;
String text = source.toString().substring(start, end);
StringBuilder str = new StringBuilder(dest.toString());
if(dstart == str.length())
{
append = true;
str.append(text);
}
else
str.replace(dstart, dend, text);
if(str.toString().contains("aaaaaaaaaaaa/*the word here*/aaaaaaaa"))
{
if(append==true)
return "";
else
return dest.subSequence(dstart, dend);
}
return null;
}
}
<EditText
android:inputType="textFilter"
android:digits="@string/myAlphaNumeric" />
<string name="myAlphaNumeric">abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789</string>
public static InputFilter filter = new InputFilter() {
@Override
public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
String blockCharacterSet = "~#^|$%*!@/()-'\":;,?{}=!$^';,?×÷<>{}€£¥₩%~`¤♡♥_|《》¡¿°•○●□■◇◆♧♣▲▼▶◀↑↓←→☆★▪:-);-):-D:-(:'(:O 1234567890";
if (source != null && blockCharacterSet.contains(("" + source))) {
return "";
}
return null;
}
};
edtText.setFilters(new InputFilter[] { filter });
editText.addTextChangedListener(new TextWatcher() {
@Override
public void afterTextChanged(Editable editable) {
super.afterTextChanged(editable);
String originalText = editable.toString();
int originalTextLength = originalText.length();
int currentSelection = editText.getSelectionStart();
// Create the filtered text
StringBuilder sb = new StringBuilder();
boolean hasChanged = false;
for (int i = 0; i < originalTextLength; i++) {
char currentChar = originalText.charAt(i);
if (isAllowed(currentChar)) {
sb.append(currentChar);
} else {
hasChanged = true;
if (currentSelection >= i) {
currentSelection--;
}
}
}
// If we filtered something, update the text and the cursor location
if (hasChanged) {
String newText = sb.toString();
editText.setText(newText);
editText.setSelection(currentSelection);
}
}
private boolean isAllowed(char c) {
// TODO: Add the filter logic here
return Character.isLetter(c) || Character.isSpaceChar(c);
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
// Do Nothing
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
// Do Nothing
}
});
public void setNameFilter() {
InputFilter filter = new InputFilter() {
@RequiresApi(api = Build.VERSION_CODES.KITKAT)
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend) {
for (int i = start; i < end; i++) {
if (dend == 0) {
if (Character.isSpaceChar(source.charAt(i)) ||
!Character.isAlphabetic(source.charAt(i))) {
return Constants.Delimiter.BLANK;
} else {
return String.valueOf(source.charAt(i)).toUpperCase();
}
} else if (Character.isSpaceChar(source.charAt(i)) &&
String.valueOf(dest).endsWith(Constants.Delimiter.ONE_SPACE)) {
return Constants.Delimiter.BLANK;
} else if ((!Character.isSpaceChar(source.charAt(i)) &&
!Character.isAlphabetic(source.charAt(i)))) {
return Constants.Delimiter.BLANK;
}
}
return null;
}
};
editText.setFilters(new InputFilter[]{filter, new InputFilter.LengthFilter(Constants.Length.NAME_LENGTH)});
}
<string name="vin_code_mask">0123456789abcdefghjklmnprstuvwxyz</string>
android:digits="@string/vin_code_mask"
edit_text.filters += InputFilter { source, start, end, _, _, _ ->
val mask = getString(R.string.vin_code_mask)
for (i in start until end) {
if (!mask.contains(source[i])) {
return@InputFilter ""
}
}
null
}
edit_text.keyListener = DigitsKeyListener.getInstance(context.getString(R.string.vin_code_mask))
/**
* Returns the filter of the editText'es CharSequence value when [filterType] is:
* 1 -> letters; 2 -> letters and digits; 3 -> digits;
* 4 -> digits and dots
*/
class InputFilterAlphanumeric(private val filterType: Int): InputFilter {
override fun filter(source: CharSequence?, start: Int, end: Int, dest: Spanned?, dstart: Int, dend: Int): CharSequence {
(source as? SpannableStringBuilder)?.let {sourceAsSpannableBuilder ->
for (i in (end - 1) downTo start) {
val currentChar = source[i]
when(filterType) {
1 -> {
if (!currentChar.isLetter() && !currentChar.isWhitespace()) {
sourceAsSpannableBuilder.delete(i, i + 1)
}
}
2 -> {
if (!currentChar.isLetterOrDigit() && !currentChar.isWhitespace()) {
sourceAsSpannableBuilder.delete(i, i + 1)
}
}
3 -> {
if (!currentChar.isDigit()) {
sourceAsSpannableBuilder.delete(i, i + 1)
}
}
4 -> {
if (!currentChar.isDigit() || !currentChar.toString().contains(".")) {
sourceAsSpannableBuilder.delete(i, i + 1)
}
}
}
}
return source
} ?: run {
val filteredStringBuilder = StringBuilder()
for (i in start until end) {
val currentChar = source?.get(i)
when(filterType) {
1 -> {
if (currentChar?.isLetter()!! || currentChar.isWhitespace()) {
filteredStringBuilder.append(currentChar)
}
}
2 -> {
if (currentChar?.isLetterOrDigit()!! || currentChar.isWhitespace()) {
filteredStringBuilder.append(currentChar)
}
}
3 -> {
if (currentChar?.isDigit()!!) {
filteredStringBuilder.append(currentChar)
}
}
4 -> {
if (currentChar?.isDigit()!! || currentChar.toString().contains(".")) {
filteredStringBuilder.append(currentChar)
}
}
}
}
return filteredStringBuilder
}
}
}
fun EditText.filterByDataType(filterType: Int) {
this.filters = arrayOf<InputFilter>(InputFilterAlphanumeric(filterType))
}
edit_text.filters = arrayOf(object : InputFilter {
override fun filter(
source: CharSequence?,
start: Int,
end: Int,
dest: Spanned?,
dstart: Int,
dend: Int
): CharSequence? {
return source?.subSequence(start, end)
?.replace(Regex("[^A-Za-z0-9 ]"), "")
}
})
val regex = Regex("[a-zA-Z\\d ]")
editText.filters = arrayOf(InputFilter { source, _, _, _, _, _ ->
source.filter { regex.matches(it.toString()) }
})