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Android 如何删除变量上的值_Android_Android Recyclerview_Recyclerview Layout_Onitemclick - Fatal编程技术网

Android 如何删除变量上的值

Android 如何删除变量上的值,android,android-recyclerview,recyclerview-layout,onitemclick,Android,Android Recyclerview,Recyclerview Layout,Onitemclick,我是Android新手,我有一个问题。 我有一个可点击的recyclerview,它将发送一个查询。单击时,它将获得所单击的每个位置的编号/ID 像这样: fno = arrivals.get(position).flightno; codeCity = arrivals.get(position).arr; 第一次单击会成功,但第二次或第三次单击会出错。我认为这是因为变量fno和codeCity已经被填充了。那么如何删除变量上的值呢 单击recyclerview时,这是我的代码: mRecy

我是Android新手,我有一个问题。 我有一个可点击的recyclerview,它将发送一个查询。单击时,它将获得所单击的每个位置的编号/ID

像这样:

fno = arrivals.get(position).flightno;
codeCity = arrivals.get(position).arr;
第一次单击会成功,但第二次或第三次单击会出错。我认为这是因为变量fno和codeCity已经被填充了。那么如何删除变量上的值呢

单击recyclerview时,这是我的代码:

mRecyclerView.addOnItemTouchListener(new RecyclerView.OnItemTouchListener() {
            GestureDetector gestureDetector = new GestureDetector(mContext, new GestureDetector.SimpleOnGestureListener() {

                public boolean onSingleTapUp(MotionEvent e){
                    return true;
                }
            });

            @Override
            public boolean onInterceptTouchEvent(RecyclerView rv, MotionEvent e) {
                View child = rv.findChildViewUnder(e.getX(), e.getY());
                if (child != null && gestureDetector.onTouchEvent(e)){
                    int position = rv.getChildAdapterPosition(child);

                    fno = arrivals.get(position).flightno;
                    codeCity = arrivals.get(position).arr;

                    final Bundle i = new Bundle();
                    i.putString("city", codeCity.toString()); // Key1
                    i.putString("flightno", fno.toString()); // Key1
                    open2(i);
                }
                return false;
            }

            @Override
            public void onTouchEvent(RecyclerView rv, MotionEvent e) {

            }

            @Override
            public void onRequestDisallowInterceptTouchEvent(boolean disallowIntercept) {

            }
        });
这就是问题所在

public void open2(Bundle args){
codeIata=args.getString(“城市”);
String flightdate=args.getString(“flightdate”);
fno=args.getString(“flightno”);
到货日期。详细信息(codeIata、航班日期、fno);
}
公共静态无效详细信息(字符串s、字符串日期、字符串fno){
DateFormat df=新的简化格式(“yyyy-MM-d”);
date=df.format(Calendar.getInstance().getTime());
调用arrCall=mApiInterface.getArr(s,“2019-03-04”,fno);
arrCall.enqueue(新回调(){
@凌驾
公共void onResponse(调用、响应
(答复){
System.out.println(“状态代码”+response.code());
arrivals=response.body().getResult();
mAdapter=新到达的dapter(mContext,到达);
//mRecyclerView.setAdapter(mAdapter);
}
@凌驾
失败时公共无效(调用调用,可丢弃的t){
Log.e(“改造Get”,t.toString());
}
});

}
有两种方法可以捕获recyclerview项上的单击事件:

第一种方法

重写
onClick
方法,而不是
onInterceptTouchEvent

我给你举个例子

mRecyclerView.addOnItemTouchListener(new RecyclerTouchListener(this,
        recyclerView, new ClickListener() {
    @Override
    public void onClick(View view, final int position) {
        fno = arrivals.get(position).flightno;
        codeCity = arrivals.get(position).arr;
    }

}));

class RecyclerTouchListener implements RecyclerView.OnItemTouchListener{

    private ClickListener clicklistener;
    private GestureDetector gestureDetector;

    public RecyclerTouchListener(Context context, final RecyclerView recycleView, final ClickListener clicklistener){

        this.clicklistener=clicklistener;
        gestureDetector=new GestureDetector(context,new GestureDetector.SimpleOnGestureListener(){
            @Override
            public boolean onSingleTapUp(MotionEvent e) {
                return true;
            }

            @Override
            public void onLongPress(MotionEvent e) {
                View child=recycleView.findChildViewUnder(e.getX(),e.getY());
                if(child!=null && clicklistener!=null){
                    clicklistener.onLongClick(child,recycleView.getChildAdapterPosition(child));
                }
            }
        });
    }

    @Override
    public boolean onInterceptTouchEvent(RecyclerView rv, MotionEvent e) {
        View child=rv.findChildViewUnder(e.getX(),e.getY());
        if(child!=null && clicklistener!=null && gestureDetector.onTouchEvent(e)){
            clicklistener.onClick(child,rv.getChildAdapterPosition(child));
        }

        return false;
    }

    @Override
    public void onTouchEvent(RecyclerView rv, MotionEvent e) {

    }

    @Override
    public void onRequestDisallowInterceptTouchEvent(boolean disallowIntercept) {

    }
}
第二种方法(更为传统的方法)

覆盖适配器的viewholder的OnClickListener:

public class MyAdapter extends RecyclerView.Adapter<MyAdapter.MyViewHolder> {

    LayoutInflater inflater;
    Context context;

    private MyAdapter.RecyclerViewClickListener mListener;

    public MyAdapter(Context context, RecyclerViewClickListener mListener) {
        this.context = context;
        this.mListener = mListener;
        inflater = LayoutInflater.from(this.context);

    }

    public class MyViewHolder extends RecyclerView.ViewHolder implements View.OnClickListener {

        public MyViewHolder(View item, RecyclerViewClickListener listener) {
            super(item);
            mListener = listener;
            item.setOnClickListener(this);
        }


        @Override
        public void onClick(View view) {
            mListener.onClick(view, getAdapterPosition());
        }
    }

    @Override
    public MyViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
        View itemView = LayoutInflater.from(parent.getContext())
                .inflate(R.layout.mylayout, parent, false);

        return new MyViewHolder(itemView,mListener);
    }
    @Override
    public void onBindViewHolder(MyViewHolder holder, int position) {

    }


    @Override
    public int getItemCount() {
        return youylist.size();
    }

    @Override
    public int getItemViewType(int position) {
        return position;
    }


    @Override
    public long getItemId(int position) {
        return 0;
    }


    public interface RecyclerViewClickListener {
        void onClick(View view, int position);
    }
}

希望这对您有所帮助。

您遇到了什么错误?您需要单击而不是单击,这样您就可以获得所单击元素的正确位置。请参考我的答案@BachVu,指向第fno=arrivals.get(position)行。flightno@Rajesh但是如果我把onClick放进Adapter我就不能发送查询我看不到任何查询,你说的是bundle值?谢谢!但什么是“回收者”呢?类?我已经实现了您的代码,但仍然得到相同的错误,仍然指向第fno=arrivals.get(position).flightno行“无效索引1,大小为1”,并且指向第fno=arrivals.get(position).flightno行
myadapter = new MyAdapter(getContext(), new MyAdapter.RecyclerViewClickListener() {
            @Override
            public void onClick(View view, int position) {
                fno = arrivals.get(position).flightno;
                codeCity = arrivals.get(position).arr;
            }
        });
        recyclerView.setAdapter(MyAdapter);
        MyAdapter.notifyDataSetChanged();