Android 安卓网络视图';s OnReceiveDhtPauthRequest()未再次调用
我使用的是一个基于webview的应用程序,其中我在webview中呈现url。该Url具有HTTP身份验证 当我第一次启动url时,会调用它的onReceiveDhtPauthRequest(),并显示一个对话框,供用户输入身份验证凭据,即auth用户名和密码Android 安卓网络视图';s OnReceiveDhtPauthRequest()未再次调用,android,webview,android-webview,basic-authentication,webviewclient,Android,Webview,Android Webview,Basic Authentication,Webviewclient,我使用的是一个基于webview的应用程序,其中我在webview中呈现url。该Url具有HTTP身份验证 当我第一次启动url时,会调用它的onReceiveDhtPauthRequest(),并显示一个对话框,供用户输入身份验证凭据,即auth用户名和密码 @Override public void onReceivedHttpAuthRequest(WebView view, HttpAuthHandler handler, String host, String realm) {
@Override
public void onReceivedHttpAuthRequest(WebView view, HttpAuthHandler handler, String host, String realm) {
final WebView mView = view;
final HttpAuthHandler mHandler = handler;
final EditText usernameInput = new EditText(mActivity);
usernameInput.setHint("Username");
final EditText passwordInput = new EditText(mActivity);
passwordInput.setHint("Password");
passwordInput.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
LinearLayout ll = new LinearLayout(mActivity);
ll.setOrientation(LinearLayout.VERTICAL);
ll.addView(usernameInput);
ll.addView(passwordInput);
Builder authDialog = new AlertDialog
.Builder(mActivity)
.setTitle("Authentication")
.setView(ll)
.setCancelable(false)
.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
mHandler.proceed(usernameInput.getText().toString(), passwordInput.getText().toString());
dialog.dismiss();
}
})
.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
dialog.dismiss();
mView.stopLoading();
onLoadListener.onAuthCancel((MyWebView)mView, mTitleTextView);
}
});
if(view!=null)
authDialog.show();
}
在提交请求时,将顺利进行并加载url。但在我使用“后退”按钮退出应用程序(不在后台发送)后,如果我再次启动应用程序并tru加载相同的url,它将直接加载url,而不要求提供凭据,并且不会再次调用OnReceiveDhtPauthRequest()
我还在使用以下代码清除应用程序退出时的凭据:
WebViewDatabase webDB = WebViewDatabase.getInstance(BrowserActivity.this);
if(webDB!=null){
if(webDB.hasFormData())
webDB.clearFormData();
if(webDB.hasUsernamePassword())
webDB.clearUsernamePassword();
if(webDB.hasHttpAuthUsernamePassword())
webDB.clearHttpAuthUsernamePassword();
}
webView.clearCache(true);
此外,我正在清除所有webview缓存、cookies和应用程序的缓存目录以及webview数据库:
BrowserActivity.this.deleteDatabase("webview.db");
BrowserActivity.this.deleteDatabase("webviewCache.db");
我不知道为什么会这样。有人能帮我吗。
至少在为什么不调用onReceiveDhtPauthRequest()的问题上?原因是webview存储以前的连接cookies。因此,我们需要手动清除它们,并为当前url存储新的cookie数据。我们可以这样做
HttpURLConnection connection = null;
try {
URL urls = new URL(url);
String authStr = "";
if (!params.isEmpty()) {
authStr = params.get(0).getValue() + ":"
+ params.get(1).getValue();
}
String authEncoded = Base64.encodeBytes(authStr.getBytes());
connection = (HttpURLConnection) urls
.openConnection();
connection.setConnectTimeout(5100);
connection.setReadTimeout(5200);
connection.setDoOutput(false);
connection.setRequestProperty("Authorization", "Basic "
+ authEncoded);
CookieManager cookieManager = CookieManager.getInstance();
String cookie = cookieManager.getCookie(connection.getURL().toString());
if (cookie != null) {
connection.setRequestProperty("Cookie", cookie);
}
connection.connect();
responseCode = connection.getResponseCode();
InputStream content = connection.getInputStream();
response = convertStreamToString(content);
content.close();
// Get cookies from responses and save into the cookie manager. session is created only in rest call url
List<String> cookieList = connection.getHeaderFields().get("Set-Cookie");
if (cookieList != null) {
for (String cookieTemp : cookieList) {
cookieManager.setCookie(connection.getURL().toString(), cookieTemp);
}
}
}catch (SocketTimeoutException es){
response = ConnectionStatus.TIME_OUT.name();
} catch (Exception e) {
response = e.getMessage();
e.printStackTrace();
}
finally {
connection.disconnect();
}
HttpURLConnection=null;
试一试{
URL URL=新URL(URL);
字符串authStr=“”;
如果(!params.isEmpty()){
authStr=params.get(0.getValue()+”:“
+参数get(1.getValue();
}
字符串authcoded=Base64.encodeBytes(authStr.getBytes());
连接=(HttpURLConnection)URL
.openConnection();
connection.setConnectTimeout(5100);
connection.setReadTimeout(5200);
连接设置输出(假);
connection.setRequestProperty(“授权”、“基本”
+作者编码);
CookieManager CookieManager=CookieManager.getInstance();
字符串cookie=cookieManager.getCookie(connection.getURL().toString());
if(cookie!=null){
setRequestProperty(“Cookie”,Cookie);
}
connection.connect();
responseCode=connection.getResponseCode();
InputStream内容=connection.getInputStream();
响应=convertStreamToString(内容);
content.close();
//从响应中获取cookie并保存到cookie管理器中。会话仅在rest调用url中创建
List cookieList=connection.getHeaderFields().get(“设置Cookie”);
如果(cookieList!=null){
for(字符串cookieTemp:cookieList){
cookieManager.setCookie(connection.getURL().toString(),cookieTemp);
}
}
}捕获(SocketTimeoutException es){
response=ConnectionStatus.TIME_OUT.name();
}捕获(例外e){
response=e.getMessage();
e、 printStackTrace();
}
最后{
连接断开();
}
loadUrl(url,extraHeader)
字符串主机,字符串域){ view.loadUrl(url);//重新加载url。
处理程序。继续(帐户、密码); }
我使用“Authorization”标题而不是OnReceiveDhtPauthRequest()解决了此问题。您确定要清除保存的用户名/密码的代码正在执行吗?是的,它正在执行。另外,当我强制停止应用程序然后启动时,它会请求auth.OK,所以听起来只有当你使用“后退”按钮时才不起作用?您究竟什么时候运行清除数据库的代码?1。正在清除Webview缓存。2.删除数据库。3.清除饼干。4.删除缓存directory@Thushara,还没有,我现在已经改变了功能。但仍然在寻找同样的东西。