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Android Firebase改为:“引用$uid==auth.uid";给出错误_Android_Firebase_Firebase Realtime Database_Firebase Authentication - Fatal编程技术网

Android Firebase改为:“引用$uid==auth.uid";给出错误

Android Firebase改为:“引用$uid==auth.uid";给出错误,android,firebase,firebase-realtime-database,firebase-authentication,Android,Firebase,Firebase Realtime Database,Firebase Authentication,身份验证中存在身份验证id。但我在尝试此操作时仍会出现此错误- DatabaseReference DatabaseReference=FirebaseDatabase.getInstance().getReference().child(“用户”).child(authResult.getUser().getUid()) 我的数据库看起来像这样- 规则是这样的- 试试“$uid===auth.uid”。我解决了android代码看起来像这样的问题- DatabaseReference data

身份验证中存在身份验证id。但我在尝试此操作时仍会出现此错误-

DatabaseReference DatabaseReference=FirebaseDatabase.getInstance().getReference().child(“用户”).child(authResult.getUser().getUid())

我的数据库看起来像这样- 规则是这样的-

试试
“$uid===auth.uid”

我解决了android代码看起来像这样的问题-

DatabaseReference databaseReference = FirebaseDatabase.getInstance().getReference().child("user").child(authResult.getUser().getUid());